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3 years ago

WUHAHAHAHHAHAH HELP ME

Mathematics

1 answer:

Nat2105 [25]3 years ago

6 0

Answer:

1. 201.06 m

2. 1963.5 dm

3. 4536.46 mm

4. 17671.46 in

5. 254.47 cm

Step-by-step explanation:

You just have to plug these numbers into the formula for area of a circle.

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Make the whole number a fraction. so if youre number is 16 make it 16/1. Then you can go on.

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3 years ago

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Qouadrilateral A has side length 6,9,9 and 12 quadrilateral B is a scaled copy of quadrilateral A, with its, shortest side of le

Naya [18.7K]

The perimeter of quadrilateral B is 12.

Explanation

Quadrilateral A has side lengths as 6, 9, 9 and 12. In quadrilateral B, length of the shortest side is 2.

As quadrilateral B is a scaled copy of quadrilateral A, so the scale factor will be...

(Shortest side of B / Shortest side of A) $=\frac{2}{6}=\frac{1}{3}$

Now the remaining side lengths for quadrilateral B will be.....

$(9*\frac{1}{3}) , (9*\frac{1}{3})$ and $(12*\frac{1}{3})$

⇒ 3 , 3 and 4

Thus, the perimeter of quadrilateral B is $= 2+3+3+4= 12$

5 0

3 years ago

An eighth-grade teacher wants to improve how the students function in small groups. What is the best strategy for improving the

WINSTONCH [101]

Answer:

I don't think you are asking a math question, but in my opinion you should choose a leader that you think would be responsible in a group, then tell them what the group needs to do.

Step-by-step explanation:

4 0

3 years ago

Use the given sample data to construct the indicated confidence interval for the population mean. The principal randomly selecte

Lunna [17]

Answer:

The 90% confidence interval

(74.71, 82.63)

Step-by-step explanation:

Confidence Interval Formula is given as:

Confidence Interval = μ ± z (σ/√n)

Where

μ = mean score

z = z score

N = number of the population

σ = standard deviation

The mean is calculated as = The average of their scores

N = 6 students

(71.6 + 81.0 + 88.9 + 80.4 + 78.1 + 72.0 )/ 6

Mean score = 472/6

= 78.666666667

≈ 78.67

We are given a confidence interval of 90% therefore the

z score = 1.645

Standard Deviation for the scores =

s=(x -σ)²/ n - 1 =(71.6 - 78.67)²+(81.0 - 78.67)²+(88.9 - 78.67)² + (80.4 - 78.67)²+ (78.1 - 78.67)²+( 72.0 - 78.67)2/ 6 - 1

= 5.886047531

= 5.89

The confidence interval is calculated as

= μ ± z (σ/√N)

= 78.67 ± 1.645(5.89/√6)

= 78.67 ± 3.9555380987

The 90% confidence interval

is :

78.67 + 3.9555380987 = 82.625538099

78.67 - 3.9555380987 = 74.714619013

Therefore, the confidence interval is approximately between

(74.71, 82.63)

3 0

3 years ago

I dont understand please help

Llana [10]

What is the question?

8 0

3 years ago

WUHAHAHAHHAHAH HELP ME​

WUHAHAHAHHAHAH HELP ME