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Agata [3.3K]
3 years ago
10

Help please!!!! Solve the system by graphing

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:

picture of graph is attached. lmk if ur getting these right. its been a while since I've dont this

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X + 2 &gt; 7 or 4 - x &gt; 6<br><img src="https://tex.z-dn.net/?f=x%20%2B%202%20%3E%207or4%20-%20x%20%3E%206%20" id="TexFormula1
Doss [256]

So, x > 7 - 2; x >5 or

4 - x > 6; 4 - x - 6 > 0;

4 - 6 -x > 0;

- 2 -x > 0;

-2 > x;

Finally, x > 5 or x < -2;

4 0
3 years ago
ANSWER FAST PLZ 33 POINTS!!!!!!!!!!!!!!!!!!
vlada-n [284]

Answer:

it is 706.5 in sq

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Questlon 3 of 10
amm1812

Answer:

b)A cube with side lengths of 4 feet has a volume of 64cubic feet

Step-by-step explanation:

volume=length×width×height

=4×4×4

=64feet³

5 0
3 years ago
If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the
Brrunno [24]

Answer:

\left(100\pi - 150\sqrt{3}\right) square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 10 inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment \sf CH be a height on side \sf AB. Since this triangle is equilateral, the size of each internal angle will be \sf 60^\circ. The length of segment

\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}.

The area (in square inches) of this equilateral triangle will be:

\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}.

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}.

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is 10 inches, the radius of this circle will also be 10 inches.

The area (in square inches) of a circle of radius 10 inches is:

\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi.

The area (in square inches) of the circle that the hexagon did not cover would be:

\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}.

3 0
3 years ago
I rlly need help pls help me
kifflom [539]

Answer:

This one ↓↓↓↓↓↓

Step-by-step explanation:

The picture attached is the reflection over the line y = 0

-Chetan K

4 0
2 years ago
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