Arturo is attempting to protect the database (data) of an information system (IS).
<h3>What is an information system?</h3>
An information system (IS) can be defined as a set of computer systems, that is typically used to collect, store, and process data, as well as the dissemination of information, knowledge, and the distribution of digital products.
In Cybersecurity, there are two (2) main techniques that can be used to check data when inputted in an information system (IS) and these include:
Data validation is a type of check which is primarily performed by a software program (application) to make sure that the data which is entered into an information system (IS) is allowable and sensible.
This ultimately implies that, any data that is not allowed or sensible are rejected and discarded by the computer system.
In conclusion, we can deduce that Arturo is attempting to protect the database (data) of an information system (IS).
Read more on data here: brainly.com/question/25885448
Answer:
This article shows how to use regex to remove spaces in between a String.
A string with spaces in between.
String text = "Hello World Java.";
We want to remove the spaces and display it as below:
Hello World Java.
1. Java regex remove spaces
In Java, we can use regex \\s+ to match whitespace characters, and replaceAll("\\s+", " ") to replace them with a single space.
Regex explanation.
`\\s` # Matches whitespace characters.
+ # One or more
StringRemoveSpaces.java
package com.mkyong.regex.string;
public class StringRemoveSpaces {
public static void main(String[] args) {
String text = "Hello World Java.";
String result = text.replaceAll("\\s+", " ");
System.out.println(result);
}
}
Output
Terminal
Hello World Java.
Answer:
The method is as follows:
double square(int num){
return num*num;
}
Explanation:
Written in C++
This first line defines the method
double square(int num){
This line returns the square of num
return num*num;
}
<em>I've added the full program as an attachment where I include the main method</em>
Answer:
1) 402.7 grams. This estimate is called the sample mean.
2) (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
Explanation:
sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams
1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.
2) c = 99% = 0.99
α = 1 - 0.99 = 0.01
.
The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).
.
The margin of error (e) = 
The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
