Answer:
6 meters
Step-by-step explanation:
Th equation to find the diameter of a circle is,
radius * 2.
The radius of the swimming pool is 3, so 3 * 2 is 6.
Hope this helps!!
Let me know if I'm wrong...
On a right triangle, to find one missing side you can use this equation
a^2 + b^2 = c^2
a and b are the sides next to the right angle, and c is the hypotenuse (side not connected to right angle).
You first need to find the length of the dotted line before finding x. This is because to be able to use the above formula, you have to know the length of two out of three of the sides.
To solve the length of the dotted line, note that it also makes a triangle with the 5 unit line and the 5 √5 unit line. You can plug these numbers into the formula.
(5)^2+b^2=(5 √5)^2
25+b^2=125
b^2=100
b=10
Now that you know the length of the dotted line is 10 units, you can now solve for x
(20)^2+(10)^2=x^2
400+100=x^2
500=x^2
x= √500, which equals 22.361
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:
<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.
<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.
If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.
The vertices of the quadrilateral ABCD lie on the sides of quadrilateral PQRS then the sum of the degree of measures of the eight indicated angles would be 360.
Answer:
16/100
Step-by-step explanation:
the decimal is 16 hundreths of one
