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Liula [17]
3 years ago
14

Find the slope. Please reply if you can help

Mathematics
2 answers:
aliina [53]3 years ago
7 0

Answer:

1/1 because you go up 1 and over 1

almond37 [142]3 years ago
6 0

Answer:

look at the picture i have sent

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If annie has 8 apples and eren has 927 ore apples then annie, how much apples does eren have?
OleMash [197]

Answer:

935 apples

Step-by-step explanation:

927 plus 8 equal 935

7 0
3 years ago
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Please help me with this
AleksAgata [21]
Count the number of digits after the first digit. this gives you the exponent on the 10. The first number in scientific form has the decimal point after the first digit.

For mercury there are 7 digits after the 5:-

So the Mercury answer is

5.7909175 * 10^7

Follow this procedure for the other planets

The answer for Venus is

1.08208930 * 10^8
4 0
4 years ago
What is the solution to this equation? 2ln4+lnx=3ln2+ln(x+1)
Galina-37 [17]

Answer:

x=1

Step-by-step explanation:

Given equation:

2 \ln 4+\ln x=3 \ln 2+\ln(x+1)

\textsf{Apply the power law}: \quad n \ln x = \ln x^n

\implies \ln 4^2+\ln x=\ln 2^3+\ln(x+1)

Simplify:

\implies \ln 16+\ln x=\ln 8+\ln(x+1)

Subtract ln 8 from both sides:

\implies \ln 16+\ln x- \ln 8=\ln(x+1)

Subtract ln x from both sides:

\implies \ln 16-\ln 8=\ln(x+1)-\ln x

\textsf{Apply the quotient law}: \quad \ln x - \ln y = \ln \frac{x}{y}

\implies \ln \left\dfrac{16}{8}\right = \ln \left(\dfrac{x+1}{x}\right)

Simplify:

\implies \ln 2 = \ln \left(\dfrac{x+1}{x}\right)

\textsf{Apply the equality law}: \quad \textsf{if }\: \ln x= \ln y\:\textsf{ then }\:x=y

\implies 2=\dfrac{x+1}{x}

Multiply both sides by x:

\implies 2x=x+1

Subtract x from both sides:

\implies x=1

5 0
2 years ago
2<br> y + 7 = 5(x - 3)<br> What is the standard form for this?
lesya [120]

Answer:

y=10/3 i think if that's what youre asking

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME FAST!!!!
adoni [48]

Answer:

A is the only possible correct answer since the center of that shape is x =-1

6 0
3 years ago
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