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tester [92]
2 years ago
8

The spherical container has a radius of 21 cm. What is the approximate volume of the container? Use 3. 14 to approximate pi. Rou

nd to the nearest hundredth if necessary. Enter your answer as a decimal in the box. Cm³.
Mathematics
1 answer:
Gemiola [76]2 years ago
6 0

Volume of a figure is the measure of the space that figure occupies. The approximate volume of the specified container is 87.92 cm³

<h3>What is the volume of sphere?</h3>

If the given sphere is of radius r units, then its volume is given as:

V=  \dfrac{4}{3} \pi r^3 \: \rm unit^3

For the given case, the radius of the sphere is given to be 21 cm, and the value of pi is instructed to be used  as 3.14

Thus, we have the volume of container as:

V = \dfrac{4}{3} \pi r^3 = \dfrac{4}{3} \times 3.14 \times 21 = 87.92 \: \rm cm^3{

Thus,

The approximate volume of the specified container is 87.92 cm³

Learn more about volume of sphere here:

brainly.com/question/381274

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\frac{2}{5}±\frac{\sqrt{17}}{5}

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(5x-2)^2=17 \\ 5x-2=±\sqrt{17} \\ 5x = 2 ± \sqrt{17}   \\ x=\frac{2}{5}± \frac{\sqrt{17}}{5}

Don't mind the ±

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3 years ago
Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat
SashulF [63]

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

<u><em>Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes</em></u>

Reasoning in the same way:

<u><em>Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes</em></u>

(b)  Now want to know when the two pools would have the same amount of water.  If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

<u><em>3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes</em></u>

5 0
3 years ago
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