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aleksklad [387]
3 years ago
9

I need help with part a and b. sorry its kind of hard to read

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

A) 4900

B) How far above she is before she starts hiking/the distance she is from the canyon floor.

Step-by-step explanation:

Since it's linear, it will follow the formula y=mx+c.

We can sub in the values to get:

3500=m(1)+c → 3500-m=c

2100=m(2)+c → 2100 = 2m+c

Sub '3500-m' in for c:

2100=2m+3500-m

m= -1400

c=3500-m=3500-(-1400)=3500+1400=4900

∴equation is: y= -1400x+4900

To find the initial value, ie when the number of hours = 0, we sub in zero for x:

y = -1400(0) + 4900

PART A ANS: 4900

PART B ANS: Since the number of hours passed is zero, the value represents how far above she is before she starts hiking/the distance she is from the canyon floor.

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lapo4ka [179]

Answer:

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Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

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y = x

Now solve these two equations.

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x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

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(1,1)

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Answer: A

Question Two

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Subtract x from both sides

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k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

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