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Tems11 [23]
3 years ago
9

Can someone please help me find the vertex? I don't know how to, well, that and I've got a major headache.

Mathematics
1 answer:
Darya [45]3 years ago
7 0

Answer:

so it = 6 since you minus 7

Step-by-step explanation:

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Which quadrant is the ordered pair (4,-10) located
vivado [14]
Quad. 4.

x is positive & y is negative.
7 0
4 years ago
Read 2 more answers
7/12 divided by 2/5 I need help thanks and bye
Law Incorporation [45]

hey there!

7/12 divided by 2/5 is 7/30

first you have to find the reciprocal for 2 / 5 can do that by flipping 2 / 5 you'll then get 5 / 2 now the rest is simple all you have to do is multiply 7/12 by 2/5 so you multiply 7 by 2 and you get 14 that's your numerator 10 divide 12 by 5 and you'll get 60 so now you have 14 / 60 7 / 30 now you simplify and you get

I hope I helped please mark me brainliest

baiiiiiii

3 0
3 years ago
The sum of two integers is 51. The larger number is 3 more than 5 times the smaller number. Find the value of the larger number
Alona [7]

Answer:

Larger number = 43

Step-by-step explanation:

Smaller number = x

Larger number = 5x + 3

Sum of two integers = 51

x + 5x + 3 = 51    

       6x + 3 = 51

             6x = 51-3

             6x = 48

               x = 48/6

                x = 8

Larger number = 5x + 3

                         = 5*8 + 3

                          = 40 + 3

                         = 43    

5 0
3 years ago
Which number(s) below belong to the solution set of the equation? Check all that apply . x + 50 = 60
nataly862011 [7]

Answer:

x + 50 = 60

x = 60 - 50

× = 10

this is the answer . It just calculation.

5 0
3 years ago
When the polynomial P(x)=ax^3+bx^2+3x-10 is divided by x+1, the remainder is -8. P(x) has a factor of x+5. Find the values of a
Ahat [919]

Answer:

a = 1, b = 6

Step-by-step explanation:

The equation given is as follows;

P(x) = a·x³ + b·x² + 3·x - 10

The above equation has a factor of x + 5, therefore, we have;

P(-5) = 0 = a·(-5)³ + b·(-5)² + 3·(-5) - 10

-125·a + 25·b + (-15) - 10 = 0

-125·a + 25·b - 25 = 0

-125·a + 25·b  = 25...........(1)

Also, we are given that;

a·x³ + b·x² + 3·x - 10 divided by x + 1 as a remainder, R = -8, therefore;

P(-1) = -8 = a·(-1)³ + b·(-1)² + 3·(-1) - 10

-a + b - 13 = -8

-a + b = -8 + 13 = 5

-a + b = 5............................(2)

Multiply equation (2) by 25 and subtract from (1) gives

-125·a + 25·b - 25(-a + b) = 25 - 25×5

-100·a = 25 - 125 = -100

a = 1

Therefore, from equation (2) we have;

-1 + b = 5

b = 5 + 1 = 6.

7 0
3 years ago
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