Answer:
there is not a complete question here ...
is not in a denominator to rationalize
if it were you would multiply the rational expression (the fraction)
by
the result (in the denominator would end up being "2 -1"
which is 1
Step-by-step explanation:
<h2>
Answer:</h2>
A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. A rectangular prism is a solid whose base is a rectangle. Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:
![V=L\times W\times H](https://tex.z-dn.net/?f=V%3DL%5Ctimes%20W%5Ctimes%20H)
FOR THE ORIGINAL PRISM WE HAVE THE FOLLOWING DIMENSIONS:
![L=14cm \\ \\ W=6cm \\ \\ H=3cm](https://tex.z-dn.net/?f=L%3D14cm%20%5C%5C%20%5C%5C%20W%3D6cm%20%5C%5C%20%5C%5C%20H%3D3cm)
In fact, the volume is
because:
![V=14\times 6\times 3 \therefore V=252cm^3](https://tex.z-dn.net/?f=V%3D14%5Ctimes%206%5Ctimes%203%20%5Ctherefore%20V%3D252cm%5E3)
Now the height of the prism was changed from 3 centimeters to 6 centimeters to create a new rectangular prism, therefore:
FOR THE NEW PRISM WE HAVE THE FOLLOWING DIMENSIONS:
![L=14cm \\ \\ W=6cm \\ \\ H=6cm](https://tex.z-dn.net/?f=L%3D14cm%20%5C%5C%20%5C%5C%20W%3D6cm%20%5C%5C%20%5C%5C%20H%3D6cm)
So the new volume is:
![V=14\times 6\times 6 \therefore V=504cm^3](https://tex.z-dn.net/?f=V%3D14%5Ctimes%206%5Ctimes%206%20%5Ctherefore%20V%3D504cm%5E3)
<h3><em>What do we know about the volume of the new prism?</em></h3>
<em>Well, the volume has increased from </em>
<em>and since</em>
<em>we can say that the new volume is two times the original volume.</em>
Answer:
![a=-2\\b=4\\c=-3](https://tex.z-dn.net/?f=a%3D-2%5C%5Cb%3D4%5C%5Cc%3D-3)
Step-by-step explanation:
In a quadratic equation in the Standard form
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero:
).
You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:
![-2x^2+4x-3=0](https://tex.z-dn.net/?f=-2x%5E2%2B4x-3%3D0)
Therefore, you can identify that the values of "a", "b" and "c" are the following:
![a=-2\\b=4\\c=-3](https://tex.z-dn.net/?f=a%3D-2%5C%5Cb%3D4%5C%5Cc%3D-3)