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evablogger [386]
3 years ago
13

Mientras que en variables discretas se utiliza la función de probabilidad, en distribuciones continuas se utiliza la función de

densidad., verdadero o falso?
Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

Answer: FIRST OPTION

Step-by-step explanation:

The missing picture is attached.

By definition, given a Quadratic equation in the form:

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

In this case, the exercise gives you this Quadratic equation:

You can identify that the numerical coefficients are:

Therefore, you can substitute values into the Quadratic formula shown above:

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

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Can someone help me with translation
Arte-miy333 [17]

Answer:

  P' = (4, 4)

Step-by-step explanation:

T(x, y) is a function of x and y. Put the x- and y-values of point P into the translation formula and do the arithmetic.

  P' = T(8, -3) = (8 -4, -3 +7) = (4, 4)

_____

<em>Comment on notation</em>

The notation can be a little confusing, as the same form is used to mean different things. Here, P(8, -3) means <em>point P</em> has coordinates x=8, y=-3. The same form is used to define the translation function:

  T(x, y) = (x -4, y+7)

In this case, T(x, y) is not point T, but is <em>a function named T</em> (for "translation function") that takes arguments x and y and gives a coordinate pair as a result.

3 0
3 years ago
Find the vertex of the parabola formed by the following quadratic function: y = 3x^2 – 6x + 2
storchak [24]
Vertex form is y=a(x-h)^2+k, so we can rearrange to that form...

y=3x^2-6x+2  subtract 2 from both sides

y-2=3x^2-6x  divide both sides by 3

(y-2)/3=x^2-2x, halve the linear coefficient, square it, add it to both sides...in this case:  (-2/2)^2=1 so

(y-2)/3+1=x^2-2x+1  now the right side is a perfect square

(y-2+3)/3=(x-1)^2

(y+1)/3=(x-1)^2  multiply both sides by 3

y+1=3(x-1)^2  subtract 1 from both sides

y=3(x-1)^2-1  so the vertex is:

(1, -1)

...

Now if you'd like you can commit to memory the vertex point for any parabola so you don't have to do the calculations like what we did above.  The vertex of any quadratic (parabola), ax^2+bx+c is:

x= -b/(2a),   y= (4ac-b^2)/(4a)

Then you will always be able to do a quick calculation of the vertex :)
7 0
4 years ago
Pls help me lol its for my final exams pls help me pass
bazaltina [42]

Answer:

lol, good luck..........

5 0
3 years ago
An electronics store is having a 15% off sale. Suppose the sale price(p) of a laptop is $495. Which statement are true for this
valentina_108 [34]

Answer:

The answer to the Question is D

5 0
3 years ago
Read 2 more answers
HURRY ILL MARK YOU THE BRAINLEST
Veseljchak [2.6K]

Answer:

C

Step-by-step explanation:

There is no way of telling what the means are.

4 0
3 years ago
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