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Genrish500 [490]
2 years ago
10

Can someone please help me??

Mathematics
2 answers:
vekshin12 years ago
8 0

Answer:

A

Step-by-step explanation:

It cannot be D, because you are subtracting the whole numbers, or B and D, because the fraction does not change.

So, if you were to solve it, you are just subtracting the whole numbers, and leaving the fraction alone. So the fraction will stay as \frac{1}{3}, while you just subtract the whole numbers.

-2+5 = 3

The answer is 3\frac{1}{3}

Finger [1]2 years ago
7 0

Answer:

2 2/3

Step-by-step explanation:

I used a calculator. -2.33-(-5)=2.67

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Which statements about the graph of the function f(x) = -x2 - 4x + 2 are true? Select three options.
Nady [450]

Answer:

Domain is all real numbers.

The range is \{y|y\le 6\}

The function is increasing over (-\infty,-2).

The function is decreasing over (-2,\infty)

The function has a positive y-intercept.

-----------------This is a guess if I had interpreted your choices correctly:

Second option: The range is \{y|y\le 6\}

Third option:  The function is increasing over (-\infty,-2).

Last option:  The function has a positive y-intercept.

I can't really read some of your choices. So you can read my above and determine which is false. If you have a question about any of what I said above please let me know.

Note: I guess those 0's are suppose to be infinities? I hopefully your function is f(x)=-x^2-4x+2.

Step-by-step explanation:

f(x)=-x^2-4x+2 is a polynomial function which mean it has domain of all real numbers.  All this sentence is really saying is that there exists a number for any value you input into -x^2-4x+2.

Now since the is a quadratic then it is a parabola. We know it is a quadratic because it is comparable to ax^2+bx+c, a \neq 0.

This means the graph sort of looks like a U or an upside down U.

It is U, when a>0.

It is upside down U, when a.

So here we have a=-1 so a which means the parabola is an upside down U.  

Let's look at the range.  We know the vertex is either the highest point (if a) or the lowest point (if a>0).

The vertex here will be the highest point, again since a.

The vertex's x-coordinate can be found by evaluating \frac{-b}{2a}:

\frac{-(-4)}{2(-1)}=\frac{4}{-2}=-2.

So the y-coordinate can be found by evaluate -x^2-4x+2 for x=-2:

-(-2)^2-4(-2)+2

-(4)+8+2

4+2

6

So the highest y-coordinate is 6.  The range is therefore (-\infty,6].

If you picture the upside down U in your mind and you know the graph is symmetrical about x=-2.

Then you know the parabola is increasing on (-\infty,-2) and decreasing on (-2,\infty).

So let's look at the intevals they have:

So on (-\infty,-2) the function is increasing.

Looking on (-4,\infty) the function is increasing on (-4,-2) but decreasing on the rest of that given interval.

The function's y-intercept can be found by putting 0 in for x:

-(0)^2-4(0)+2

-0-0+2

0+2

2

The y-intercept is positive since 2>0.

8 0
3 years ago
Need the help asp!!!
Bond [772]

Answer:

It would be 8

Step-by-step explanation:

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