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3 years ago

8

Can someone help me please. i will give you a brainliest. thanks!

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

sry don't know but can u give me brainlliest

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A ball is thro.d hit the grouvelocity)?

kati45 [8]

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of height 61.9 m. So that the velocity can be determined by;

u = $\sqrt{\frac{2H}{g} }$

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/ $s^{2}$ , then;

u = $\sqrt{\frac{2*61.9}{10} }$

= $\sqrt{\frac{123.8}{10} }$

u = 3.5185

The velocity of the ball is 3.52 m/s.

3 0

4 years ago

For a wavelength of 420 nm, a diffraction grating produces a bright fringe at an angle of 24°. For an unknown wavelength, the sa

Inessa [10]

Answer:

649.8420 nm

Explanation:

We have given $\Theta _1=24^{\circ} \ and\ \Theta _2=39^{\circ}$

$\lambda _1=420\ nm$ we have to find unknown wavelength that is $\lambda _2$

The condition for constructive interference is $dsin\Theta =n\lambda$

Where d is distance between slits $\Theta$ is angle of emergence and n is order of maxima

Using constructive interference equation

$dsin\Theta _1=n\lambda _1$ ---------eqn 1

$dsin\Theta _2=n\lambda _2$ ---------eqn 2

On dividing eqn 1 by eqn 2

$\frac{\lambda _1}{\lambda _2}=\frac{sin\Theta _1}{sin\Theta _2}$

$\frac{420}{\lambda _2}=\frac{sin24^{\circ}}{sin39^{\circ}}$

$\lambda _2=649.8420\ nm$

7 0

3 years ago

Question 4 of 10 (1 point) Jump to Question: Choose the word that best completes this sentence. A personal fall arrest system is

lisabon 2012 [21]

B
is the most logical answer to me

6 0

3 years ago

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A piece of gum is stuck to the outer edge of a horizontal turntable, which is revolving at a constant speed. The shadow of the g

cestrela7 [59]

Answer:

angular frequency of the table must be same as the frequency of the projection of the gum on the wall

Explanation:

Since we know that the projection on the wall is the vertical component of the position of the gum on the rotating table

So here we will say

$y = R sin\theta$

so the angle made by the radius vector depends on the angular frequency of the disc by which it is rotating

So we can say

$\theta = \omega t$

so here we can say

$y = R sin(\omega t)$

so here we can say that

angular frequency of the table must be same as the frequency of the projection of the gum on the wall

7 0

3 years ago

Which statement describes an essential characteristic of data in an experiment?

MAVERICK [17]

The whole of the data that you have researched on

3 0

4 years ago

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