Answer:
The speed of proton when it emerges through the hole in the positive plate is 
.
Explanation:
Given that,
A parallel-plate capacitor is held at a potential difference of 250 V.
A A proton is fired toward a small hole in the negative plate with a speed of, 
We need to find the speed when it emerges through the hole in the positive plate. It can be calculated using the conservation of energy as :
So, the speed of proton when it emerges through the hole in the positive plate is .
Answer: 4550 Joules
The formula for potential energy in gravitational field is as follows:
Answer
Together with glycolysis, The Krebs cycle, and the electron transport chain release about 36 molecules of ATP per molecule of glucose.The Krebs cycle uses the two molecules of pyruvic acid formed in glycolysis and yields high-energy molecules of NADH and flavin adenine dinucleotide (FADH2), as well as some ATP. The electron transport chain forms a proton gradient across the inner mitochondrial membrane, which drives the synthesis of ATP
Answer: velocity
Explanation: it's the rate of change of the objects position/ consistent change
