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ryzh [129]
4 years ago
12

There is a simple pattern for determining if a binary number is odd. what is it and why does this pattern occur

Physics
2 answers:
Dmitry [639]4 years ago
6 0

There is a simple pattern for determining if a binary number is odd. This is when the number ends in 1. This pattern occured because they are defined by an odd word.

<h3>Further explanation </h3>

The binary number is a number that expressed in the base-2 numeral system or binary numeral system, that uses only two symbols, typically "0" and "1".

If the number ends in 1, it will be odd, whereas if the number ends in 0, it's even. Because the first digit can only be 0 or 1, the rest of the digits are multiplied by two.  To convert a binary number to base 2k, split it into groups of k digits by adding leading 0s if necessary, then convert each group to base 2k.

Example:

  • 1001 represents an odd number (9)
  • 1000 represents an even number (8)
  • 1101 represents an odd number (13)
  • 10010 represents an even number (18).

This pattern odd occured because they are defined by an odd word.They are numbers, that are by definition is too many things that they become odd, and also because they look odd again even when split into two

<h3>Learn more</h3>
  1. Learn more about binary number brainly.com/question/8604586
  2. Learn more about pattern brainly.com/question/554926
  3. Learn more about odd binary number brainly.com/question/5625911

<h3>Answer details</h3>

Grade:  9

Subject:  physics

Chapter:  Computer Science

Keywords: binary number, pattern, odd binary number, even binary number, Computer Science

frez [133]4 years ago
5 0
The answer to this question would be the least number (right most number).

If you add an even number with even number, the result should be even. But if there is just one odd number added, it will be odd.
In binary, all the number is multiplied by 2^{x}. It is pretty clear that all the number should be even beside the first/lowest multiplier 2^{0}  which has potential to be 1. 
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Answer:

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b) Andrea's final momentum, 0

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d) The force that the seat belt exerts on Andrea, - 400 N

Explanation:

Given data,

The initial velocity of the car is, u = 40 m/s

The mass of Andrea, m = 50 kg

The time period of deceleration, a = 0.5 s

The final velocity of the car, v = 0

a) Andrea's initial momentum,

               p = mu

                  = 50 x 40

                  = 200 kg m/s

b) Andrea's final momentum

                  P = mv

                     = 50 x 0

                    = 0 kg m/s

c) Impulse

                   I = mv - mu

                     = 0 - 200

                    = - 200 Ns

The negative sign indicated that the momentum is decreased.

d) The force that the seat belt exerts on Andrea

                   F = (mv - mu)t

                     = (0 - 200) / 0.5

                     = - 400 Ns

Hence,the force that the seat belt exerts on Andrea is, - 400 N

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