All categories

2 years ago

How are humidity and relative humidity different?

2 answers:

7 0

The Humidity Ratio is how much ‘air’ is in the air versus the amount of water. Relative Humidity on the other hand, takes the humidity ratio, and includes the air temperature, and the maximum amount of water the air can hold, and displays it as a percentage.

mr_godi [17]2 years ago

6 0

Relative humidity is the percentage of what it can hold. Humidity is the measure of the amount of water vapor it can hold.

hope this helps ^^

You might be interested in

Astroturf is a durable artificial surface used to cover athletic fields. A soccer field 0.06214- mile-long by 253 ft wide is cov

love history [14]

Answer:

The weight of the Astroturf is 179,684.31 Newtons.

Explanation:

Length of a soccer field = 0.06214 mile = 328.0992 feet

(1 mile = 5280 feet)

Breadth of a soccer field = 253 feet

Length of a Astroturf which soccer field is to be covered, l = 328.0992 feet

Breadth of a Astroturf which soccer field is to be covered ,b = 253 feet

Thickness of a Astroturf with which soccer field is to be covered = h

h = ½ inch = 0.5 inch = 0.041665 feet

(1 inches = 0.08333 feet)

Volume of the Astroturf ,V= l × b × h

$V=328.0992 ft\times 253 ft\times 0.041665 ft=3,458.574 ft^3$

Mass of the Astroturf = m

Density of the Astroturf = d = 187 $oz/ft^3$

$d=\frac{m}{V}$

$m=d\times V= 187 oz/ft^3\times 3,458.574 ft^3=646,753.35 oz$

1 oz = 0.0283495 kg

$m=646,743.35 oz=646,743.35\times 0.0283495 kg=18,335.13 kg$

Weight of the Astroturf = W

W = mg

$=W=18,335.13 kg\times 9.8 m/s^2=179,684.31 N$

The weight of the Astroturf is 179,684.31 Newtons.

8 0

3 years ago

When the equation Al2(SO4)3 + NaOH + Al(OH)3 + Na2SO4 is correctly balanced, what is the coefficient of Al(OH)3?

nevsk [136]

The balanced chemical formula should be Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4

Therefore the coefficient of Al(OH)3 is 2!

Hope that helps :)

4 0

2 years ago

An atom of gold has a mass of 3.271 x 10-22g. How many atoms of gold are in 5.00g of gold?

rosijanka [135]

To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation $\frac{mass of gold}{mass of gold atom}$ .

Let x be the number of gold atoms. Plug in the values to a calculator.

x = $\frac{5.00g}{3.271 x 10-22g}$
Both have the same units so the unit gram(g) can be cancelled.
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold

3 0

3 years ago

The active form of vitamin D is called ________.

alexandr1967 [171]

<span>Calcitriol </span>is the active form of vitamin D. (D)

7 0

3 years ago

Read 2 more answers

Nitrogen has two isotopes. One has an atomic mass of 14.003

Ilia_Sergeevich [38]

Answer:

d= 14.007 amu

Explanation:

Abundance of N¹⁴ = 99.63%

Abundance of N¹⁵ = 0.37%

Atomic mass of N¹⁴ = 14.003 amu

Atomic mass of N¹⁵ = 15.000 amu

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100

Average atomic mass = (14.003 × 99.63)+(15.000× 0.37) /100

Average atomic mass = 1395.12 + 5.55 / 100

Average atomic mass = 1400.67/ 100

Average atomic mass = 14.007 amu.

6 0

2 years ago