Answer:
Step-by-step explanation:
Let's begin by factoring x^2 + 9x - 10
When you do that you get
(x - 1) (x + 10)
If that can be done then let x^(2n) + 9^n - 10 be factored into
(x^n - 1) (x^n + 10) Both of these can be equated to zero.
x^n - 1 = 0
x^n = 1
Take the nth root of both sides
No matter what n is the root of 1 is still going to be 1
x^n + 10 = 0
x^n = - 10
This one is a little harder. It depends whether n is odd or even. It it is odd, no problem. The nth root of - 10 can be found.
For example, suppose n = 5. Then the 5th root of -10 is - 1.58
You can find this on your calculator by doing
(-)
10
y^x or x^y or ^ [whichever your calculator has]
=
and you should get - 1.58
======================
If n is even, you have a problem. If you do not know what complex numbers are, they this problem has not meaning. If n = 6, then you can take the sixth of 10. Then the answer becomes If you do know what then the answer becomes 1.468i. I would say if n is even there is no solution.
<span>Before Tim ate any of the jellybeans, here are numbers:
pineapple or p =10
raspberry or r = 10
orange or o = 10
</span>Tim has eaten 6 orange <span>and 4 pineapple jellybeans. Hence, what's left are:
</span>
<span> p = 10-4 =6
o = 10-6 =4
r = 10
so now total jelly beans are 20
So the probability of getting a raspberry is:
p(r) = number of r/total
10/20 or 50%</span>
From greatest to least or least to greatest?
x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
