116/21 hope this helped !
<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer: second Congress
Step-by-step explanation:
Short and sweet
Answer: -9
Step-by-step explanation:
(6+3)÷(4-5)
Since 6+3 is 9 and 4-5 = -1
You do 9 divided by -1. It equals -9.
It is -9 since a positive divided by a negative number.
Answer:
26
Step-by-step explanation:
if YZ bisects VW then VX = XW
if VX = 26 then XW = 26 also
