All categories

3 years ago

PLS HELP I will give branliest

Mathematics

1 answer:

iren2701 [21]3 years ago

7 0

Your answer will be 130 i think ,, pretty sure though

You might be interested in

If x,y and z are the first three terms of an geometric sequence, show that x^2,y^2 and z^2 form another geometric sequence

olganol [36]

x y z are in geometric
x/y = y/z
OR y^2=xz

x^2, y^2, z^2

x^2, xz, z^2
If they are in geometric sequence then
xz/x^2 = z^2/xz
z/x = z/x
The ratios are common
so x^2,y^2 & z^2 is a GP.

8 0

3 years ago

1. Choose the correct symbol to compare. 8/10 3/4 < > =

oksano4ka [1.4K]

Answer:

I think 8/10 is greater?

3 0

3 years ago

Read 2 more answers

If it takes Joan 10 weeks to make 2 dollhouses, how long will it take her to make 15 dollhouses?

Lorico [155]

Just do 10 x 15
=150

6 0

3 years ago

Read 2 more answers

If x=17, then 27+x=y. What does y equal?

svet-max [94.6K]

Answer:

44=y

Step-by-step explanation:

27+x=y

We know x = 17, so we can substitute x=17 into the equation

27 + 17 = y

44=y

7 0

4 years ago

Read 2 more answers

X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4

nignag [31]

Standard reduction of order procedure: suppose there is a second solution of the form $y_2(x)=v(x)y_1(x)$ , which has derivatives

$y_2=vx^4$
${y_2}'=v'x^4+4vx^3$
${y_2}''=v''x^4+8v'x^3+12vx^2$

Substitute these terms into the ODE:

$x^2(v''x^4+8v'x^3+12vx^2)-7x(v'x^4+4vx^3)+16vx^4=0$
$v''x^6+8v'x^5+12vx^4-7v'x^5-28vx^4+16vx^4=0$
$v''x^6+v'x^5=0$

and replacing $v'=w$ , we have an ODE linear in $w$ :

$w'x^6+wx^5=0$

Divide both sides by $x^5$ , giving

$w'x+w=0$

and noting that the left hand side is a derivative of a product, namely

$\dfrac{\mathrm d}{\mathrm dx}[wx]=0$

we can then integrate both sides to obtain

$wx=C_1$
$w=\dfrac{C_1}x$

Solve for $v$ :

$v'=\dfrac{C_1}x$
$v=C_1\ln|x|+C_2$

Now

$y=C_1x^4\ln|x|+C_2x^4$

where the second term is already accounted for by $y_1$ , which means $y_2=x^4\ln x$ , and the above is the general solution for the ODE.

4 0

3 years ago