Help pls! Answer choices listed. Sorry that it’s blurry

Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr

drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

$AC^2= AB^2+BC^2$

$\Rightarrow (x+3)^2=x^2+8^2$

$\Rightarrow x^2+6x+9=x^2+64$

$\Rightarrow 6x=64-9=55$

$\Rightarrow x=55/6=9.17$ chi.

Hence, the height of the pole, $AB=x=9.17$ chi,

and the length of the rope, $x+3=9.17+3=12.17$ chi.

8 0

3 years ago

Literally answer any of the questions above and it’ll be the biggest help

Tcecarenko [31]

The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.

We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.

a) The cosine values repeat every 2π, so the general form of the smallest angle will be

... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ

b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is

... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ

c) Using these expressions with k=0, 1, 2, we get

... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}

3 0

4 years ago

Let each Square represent 1/3 unit by 1/3 unit.

Varvara68 [4.7K]

(5/3)*(7/3) = 35*(1/3)²

The area is 35 square units.

7 0

4 years ago

Cameron sponsor a fun raiser that 582 people attended he raise $6480 he charged $15 for balcony seats and $10 for crown seats ho

bagirrra123 [75]

Answer:

132 people bought balcony tickets and 450 bout ground tickets

Step-by-step explanation:

let x be balcony and y for ground

x+y=582

15x+10y=6480 solve by adding(subtracting)/eliminating process

multiply first equation by 15 to eliminate x:

15x+15y=8730

15x+10y=6480 subtract

15x+15y-15x-10y=8730-6480

5y=2250

y=2250/5=450

x+y=582

x=582-450=132

8 0

3 years ago

To 5% - (8.1 + 5%).<br> What’s the answer

Svetllana [295]

Answer:

rawr

Step-by-step explanation:

5 0

4 years ago

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