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Andrews [41]
3 years ago
5

PLEASE HELP!! URGENT!! WILL GIVE BRAINLIEST TO FASTEST ANSWER!! TAKING TEST ON EDGE 2020!!

Mathematics
1 answer:
Leto [7]3 years ago
3 0

Answer:

expressions which represent exponential decay:

A. 900(0.05)^t

B. 700(0.9)^x

Step-by-step explanation:

Exponential decay functions has the next form:

y = ab^x

where b < 1

A. 900(0.05)^t , a = 900, b = 0.05, the variable is t instead of x. 0.05 < 1, then it represents exponential decay

B. 700(0.9)^x , a = 700, b = 0.9 < 1, then it represents exponential decay

C. 53(1.75)^(0.3x) =  53(1.75)^(0.3)(1.75)^x, a =  53(1.75)^(0.3), b = 1.75 > 1, then it doesn't represent exponential decay

D. 90(1.2)^t, a = 90, b = 1.2 > 1,  then it doesn't represent exponential decay. (the variable is t instead of x)

E. .300(2.4)^(1.2y)  = 300(2.4)^(1.2)(2.4)^y, a = 300(2.4)^(1.2),  b = 2.4 > 1, then it doesn't represent exponential decay. (the variable is y instead of x)

F. 2x² + 9 , this is a quadratic function,  then it doesn't represent exponential decay.

G. 18 – 3y, this is a linear function,  then it doesn't represent exponential decay.

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ANSWER:

r = \frac{1}{cos2(theta)}

Explaination:

Convert the given curve into the the polar form.

x = rcosθ

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in f(x,y) = (x²-y²) - √(x²+y²) = 0

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We get at,

g(r,θ) = (r²cos²θ - r²sin²θ) - √(r²cos²θ + r²sin²θ) = 0

g(r,θ) = r²(cos²θ - sin²θ) - √r² = 0

We know that,

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