Similar and same shape........
Answer:
Step-by-step explanation:
Given: quadrilateral ABCD inscribed in a circle
To Prove:
1. ∠A and ∠C are supplementary.
2. ∠B and ∠D are supplementary.
Construction : Join AC and BD.
Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,
∠1=∠2-----(1)
∠3=∠4-----(2)
∠5=∠6-------(3)
∠7=∠8------(4)
Also, sum of angles of quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°
→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4
→→→2∠1+2∠4+2∠6+2∠8=360°
→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,
→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)
As, ∠A+∠B+∠C+∠D=360°
∠A+∠C+180°=360°
∠A+∠C=360°-180°------Using A
∠A+∠C=180°
Hence proved.
credit: someone else
l = 2w - 4
Because we're solving for 2l + 2w, that can be simplified to
2(2w - 4) + 2w = 34
4w - 8 + 2w = 34
6w - 8 = 34
6w = 42
w = 7
Knowing this, we can input w:
2(7) + 2l = 34
14 + 2L = 34
2l = 20
l = 10
L = 10, W = 7, Option C
1st data set:
Minimum: 34
1st quartile: 35
Median: 36
3rd quartile: 37
Maximum: 38
Second data set:
Minimum: 20
1st quartile: 23
Median: 25
3rd quartile: 38
Maximum: 65
Graph
it based on the values of the 1st and 3rd quartile. If they are both
the same number away from the mean then they are symmetrical. Otherwise
they are not. In this case, the first one is similar and the second one
is not.
Please mark as brainiest!
Cheers
