To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg.
<span>a) d = 1/2 (vt), = 1/2 (18 x .17), = 1.53m. </span>
<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
<span>f = (ma), = .226 x 105.88, = 23.92N. </span>
No she not correct. 80% of the students are wearing tennis shoes
It would be b because if you take 10 and shusbejsjdhebe
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Answer:
(b) 112.2 ft
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
For the given geometry, this becomes ...
tan(65°) = (height above eye level)/(50 ft)
Then we have ...
(height above eye level) = (50 ft)tan(65°) = 107.2 ft
Adding the height of eye level will give us the height of the building.
building height = (eye level height) + (height above eye level)
building height = (5 ft) + (107.2 ft)
building height = 112.2 ft
