aP and BQ are the bisectors of the two alternate interior angles formed by the intersection of a transversal t with parallel lines l and m .. Show that AP || BQ. .its a example i just gave.
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The next three terms are: -3, 6, and 15
To get each new term, we simply add 9 to the last term. So we add 9 to -12 to get -3. Then we add 9 to -3 to get 6. Finally we add 9 to 6 to get 15
In other words,
first term = -12
second term = first term+9 = -12+9 = -3
third term = second term + 9 = -3+9 = 6
fourth term = third term + 9 = 6+9 = 15
This process repeats forever though we only need three terms in this case.
So that's why the answer is the three values -3, 6 and 15
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