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Colt1911 [192]
3 years ago
14

Write the equation of a line parallel to the line y = 2x that passes through 0,4

Mathematics
1 answer:
lidiya [134]3 years ago
3 0

<u>Note: this answer assumes that the question accepts the equation to be written in slope-intercept form. </u>

Answer:

y = 2x + 4

Step-by-step explanation:

To write an equation of a line knowing a slope and a y-intercept, you can use slope-intercept form, or y = mx+ b.

1) Lines that are parallel to each other have the same slope. The answer needs to be parallel to the line y = 2x, so whatever the slope of that equation is must be the slope of the answer, too.

y is isolated in y = 2x, meaning it is in slope-intercept form, or y = mx +b form. The m in y = mx + b represents the slope of the line. In the equation y = 2x, the 2 is in the place of that m - meaning that 2 is the slope of that line, and therefore the slope of the answer, too.

2) The question also says that (0,4) is a point the line must pass through as well. However, notice that the x-value of the point is 0, meaning it is positioned on the y-intercept. Therefore, (0,4) must be the y-intercept of the equation.

3) To write a linear equation with y = mx + b form, you need to replace the m and the b for real values. The slope is 2, and m represents the slope - so write 2 in place of the m. The b represents the y-value of the y-intercept point - knowing that point is (0,4), write 4 in place of the b. Therefore, the answer would be y = 2x + 4 <u>(assuming the question can be written in slope-intercept form)</u>.

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Without multiplying all the terms, verify these equalities. a) 10!= 6!7! b) 10!=7!5!3! c) 16!= 14!5!2! d) 9!=7!3!3!2!
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Answer:

a)10! = 6×5×4×3×2 ×7!

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b)10! = 3! × 5! × 7! = 7!5!3! (Verified)

c)16! = 2! × 5! × 14!

16! = 14!5!2! (Verified)

d)9! = 3! × 3! ×2! × 7!

9! = 7!3!3!2! (Verified)

Step-by-step explanation:

a) 10!= 6!7!

10! = 10×9×8×7!

Reducing to their lowest factors

10! = (2×5)×(3×3)×(2×2×2) × 7!

Rearranging the factors, we have;

10! = (2×3)×(5)×(2×2)×(3)×2 × 7!

10! = 6×5×4×3×2 ×7!

10! = 6! 7! (Verified)

b) 10!=7!5!3!

10! = 10×9×8×7!

10! = (2×5)×(3×3)×(2×2×2) × 7!

Rearranging the factors, we have;

10! = (2×3)×(5)×(2×2)×(3)×2× 7!

10! = (3×2×1) × (5×4×3×2×1) × 7!

10! = 3! × 5! × 7! = 7!5!3! (Verified)

c) 16!= 14!5!2!

16! = 16×15×14!

16! = (2×2×2×2) × (5×3) × 14!

Rearranging the factors.

16! = (2) × (5) × (2×2) × (3) × (2) ×14!

16! = (2!) ×(5×4×3×2) × 14!

16! = 2! × 5! × 14!

16! = 14!5!2! (Verified)

d) 9!=7!3!3!2

9! = 9×8×7!

9! = (3×3) × (2×2×2) × 7!

Rearranging the factors

9! = (3×2) ×(3×2) ×(2) × 7!

9! = 3! × 3! ×2! × 7!

9! = 7!3!3!2! (Verified)

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