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3 years ago

SUBJECT: inverse Trigonometric Ratios please help me asap

Mathematics

1 answer:

san4es73 [151]3 years ago

4 0

Answer:

sert

Step-by-step explanation:

Which two of the following sentences from the article include central ideas of the article?

In 43 B.C., Octavian, Antony and Marcus Aemilus Lepidus established the Second Triumvirate.

Cleopatra’s seized treasure allowed him to pay his soldiers, making them more loyal.

During his 40-year rule, Augustus nearly doubled the size of the empire.

The family tree became more tricky after Augustus had his stepson Tiberius briefly marry his daughter, and then adopted Tiberius outright as son in A.D. 4 and named him next in line to rule.Which two of the following sentences from the article include central ideas of the article?

In 43 B.C., Octavian, Antony and Marcus Aemilus Lepidus established the Second Triumvirate.

Cleopatra’s seized treasure allowed him to pay his soldiers, making them more loyal.

During his 40-year rule, Augustus nearly doubled the size of the empire.

The family tree became more tricky after Augustus had his stepson Tiberius briefly marry his daughter, and then adopted Tiberius outright as son in A.D. 4 and named him next in line to rule.

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Please answer this question now

Ivan

Answer:

Approximately 439.6 square millimeters.

Step-by-step explanation:

The formula for the surface area of a cone is the following:

$A=\pi r^2+\pi r l$

Where, r is the radius and l is the slant height.

The radius is 7 and the slant height is 13. We also use 3.14 for π Thus:

$A=(3.14)(7)^2+(3.14)(7)(13)\\\text{Use a Calculator}\\A\approx 439.6$

5 0

3 years ago

Read 2 more answers

A quadrilateral has its four points at the coordinates (1,1) , (-3,1) , (1,4) , & (-3,4). What type of quadrilateral is it?

Lady bird [3.3K]

It's is a square and you know just by graphing it

3 0

3 years ago

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

$r_1_,_2=\lambda \pm \mu i$

Let's find the solution for $x''+x=0$ using the previous information:

The characteristic equation is:

$r^{2} +1=0$

So, the roots are given by:

$r_1_,_2=0\pm \sqrt{-1} =\pm i$

Therefore, the solution is:

$x(t)=c_1cos(t)+c_2sin(t)$

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of $x(t)$ in order to find the constants $c_1$ and $c_2$ :

$x'(t)=-c_1sin(t)+c_2cos(t)$

Evaluating the initial conditions:

$x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1$

And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

$x=-cos(t)+2sin(t)$

3 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

3 years ago

Please help would mean a lot

jarptica [38.1K]

Answer:

1/2

Step-by-step explanation:

output devided by input

3 0

2 years ago