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Troyanec [42]
3 years ago
11

Can someone please help me out

Mathematics
1 answer:
Elis [28]3 years ago
6 0
The picture that you attached says it is unavailable
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Can I have some help on these two math questions?
BigorU [14]
8. 1,728 i did 12×18÷2=108×32=345÷2= 1,728
8 0
3 years ago
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
DedPeter [7]
(a) First find the intersections of y=e^{2x-x^2} and y=2:

2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}

So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line y=1 with y=e^{2x-x^2}.

1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2

So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve y=e^{2x-x^2} and the line y=1, or e^{2x-x^2}-1. The area of any such circle is \pi times the square of its radius. Since the curve intersects the axis of revolution at x=0 and x=2, the volume would be given by

\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
5 0
3 years ago
Jessica is measuring two line segments. The first line segment is 30 cm long. The secon line segment is 500mm long. In centimete
igor_vitrenko [27]
Well 500 mm = 50 cm so if you add both segments together you will get a 50+30=80cm segment
7 0
3 years ago
The dog in the pet shop are fed at 8:30 a.m and 5:30 p.m
Feliz [49]
Your answer would be 9 hours 
4 0
3 years ago
Read 2 more answers
Find an equation for the nth term of the arithmetic sequence. a19 = -58, a21 = -164
Elodia [21]
So the formula would be -1856 +98[n-1]
8 0
3 years ago
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