This is true, because everyone has a fair chance
Check the picture below, so let's check the equations below hmmm
![\boxed{A}\\\\ y=\cfrac{16-3x}{4}\implies y=\cfrac{-3x+16}{4}\implies y = \cfrac{-3x}{4}+\cfrac{16}{4}\implies y=-\cfrac{3}{4}x\stackrel{\stackrel{b}{\downarrow }}{+4}~\hfill \bigotimes \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cboxed%7BA%7D%5C%5C%5C%5C%20y%3D%5Ccfrac%7B16-3x%7D%7B4%7D%5Cimplies%20y%3D%5Ccfrac%7B-3x%2B16%7D%7B4%7D%5Cimplies%20y%20%3D%20%5Ccfrac%7B-3x%7D%7B4%7D%2B%5Ccfrac%7B16%7D%7B4%7D%5Cimplies%20y%3D-%5Ccfrac%7B3%7D%7B4%7Dx%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B4%7D~%5Chfill%20%5Cbigotimes%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Answer:
The domain and the range of the function are, respectively:
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
Step-by-step explanation:
Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
Answer:
3√41
Step-by-step explanation:
The diagonal can be gotten using the pythagoras theorem
d² = l²+w²
d² = 12²+15²
d² = 144 + 225
d² = 369
d = √9*41
d = 3√41
Hence the diagonal is 3√41