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Archy [21]
3 years ago
7

A small toy block shaped like a right rectangular prism measures 6 cm long, 3 cm wide, and 2 cm high. What is the volume of the

toy block?
Mathematics
1 answer:
nevsk [136]3 years ago
3 0

36cm³

Step-by-step explanation:

Volume= mass

density

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Describe how to solve the inequality 3x+4<13 using algebra tiles
vladimir1956 [14]

The solution is x < 3.

Solution:

The given expression is 3x + 4 < 13.

To solve the given inequality.

3x + 4 < 13

Subtract 4 tiles on both sides of the inequality.

⇒ 3x + 4 – 4 < 13 – 4

⇒ 3x < 9

Divide by 3 tiles on both sides of the inequality.

⇒ \frac{3x}{3} =\frac{9}{3}

⇒ x < 3

Hence the solution is x < 3.

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2 years ago
6x-27=-3x<br><br> solve for x:D
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6×-27=-3×

+3×

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Choose the graph below that meets all three of the following requirements:
zmey [24]

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Your answer would be D

Step-by-step explanation:

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3 years ago
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Matt gave 5 apples to his son and sold 8 times as many apples. If Matt had 1/2 of the apples left, how many did he have in the b
Gala2k [10]

Answer:

90

Step-by-step explanation:

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4 0
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Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

#SPJ1

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2 years ago
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