What this question simply asks about is you write the numbers it gave you in only one digit by 10 to the power of n. Where n represents the number of shifts of the decimal point.
And to get this number to be one digit, then you have to approximate.
To approximate; you should always consider that less than 5 counts zero and 5 or more counts+1.
Example:
5.3 is approximately 5
5.5 is approx. 6
5.9 is also approx. 6
and so on.
So the final answers are;
1) 4*10^13
2) 5*10^-11
Please note that 10^positive integer will cause the decimal point to move to the right which means a number greater than 1, usually, while 10^negative integer means number smaller than 1, usually.
Hope this helps.
Well i havent read the story but from context clues id say its B
The system of linear equations represents the situation is;
x + y = 125
x + y = 1255x + 8y = 775
<h3>Simultaneous equation</h3>
Simultaneous equation is an equation in two unknown values are being solved for at the same time.
let
- number of quick washes = x
- number of premium washes = y
x + y = 125
5x + 8y = 775
From equation (1)
x = 125 - y
5x + 8y = 775
5(125 - y) + 8y = 775
625 - 5y + 8y = 775
- 5y + 8y = 775 - 625
3y = 150
y = 150/3
y = 50
x + y = 125
x + 50 = 125
x = 125 - 50
x = 75
Therefore, the number of quick washes and premium washes Monica’s school band had is 75 and 50 respectively.
Learn more about simultaneous equation:
brainly.com/question/16863577
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Answer:
Volume of tennis ball = 11.49 inch³
Step-by-step explanation:
Given:
Radius of tennis ball = 1.4 inches
Value of π = 3.14
Find:
Volume of tennis ball
Computation:
Volume of sphere = [4/3][π][r]³
Volume of tennis ball = [4/3][π][Radius of tennis ball]³
Volume of tennis ball = [4/3][3.14][1.4]³
Volume of tennis ball = [1.333][3.14][1.4]³
Volume of tennis ball = [1.333][3.14][2.744]
Volume of tennis ball = [4.1856][2.744]
Volume of tennis ball = 11.4852
Volume of tennis ball = 11.49 inch³
The domain and the range of the function are all possible values of the x and y, respectively, that function can take.
The range is given by:
The domain is given by:
