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Igoryamba
2 years ago
9

What is the slope of the line that passes through the points (3,-5) and (1,-5)? Write in simplest form

Mathematics
1 answer:
Gre4nikov [31]2 years ago
7 0

Answer:

The slope is apperently 5 and i rlly don't have a step-to-step explaintion but my teacher explained it and said it was 5 slopes.

Step-by-step explanation:

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Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper c
svp [43]

Answer:

0.2839 = 28.93%

Step-by-step explanation:

In order to find find the probability that one car chosen at random will have less than 68.5 tons of coal, we have to find z

Le x be tons of coal in a car

Z = (x – mean)/standard deviation

Z = (x – μ)/ σ

P (x<68.5) = P(z < (68.5-69)/0.9)

P (x<68.5) = P(z < -0.5555)

Then we use the z table to find the area under the curve.

P (x<68.5) = 0.2893

5 0
3 years ago
Can someone just tell me which ones are correct and which ones are wrong?
lozanna [386]
First row all correct second rows all wrong and the first on of third row is correct be the last two are incorrect
6 0
3 years ago
I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

5 0
3 years ago
Imagine that you write each letter of the word excellent on a different card and then shuffle the card, you turn the deck of car
salantis [7]

the answer above ^^^^

6 0
3 years ago
Read 2 more answers
I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ
kumpel [21]

Answer:

side of 6.124 ft and height of 3.674 ft

Step-by-step explanation:

Let's s be the side of the square base and h be the height of the rectangular box.

The base and the roof would have an area of s^2 and cost of

4s^2 + 2s^2 = 6s^2

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh

So the total cost for the material is

6s^2 + 10sh = 450

10sh = 450 - 6s^2

h = 45/s - 0.6s

The volume of the shed has the following formula

V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3

To find the maximum value for V, we can take its first derivative, and set it to 0

\frac{dV}{ds} = 45 - 1.2s^2 = 0

1.2s^2 = 45

s^2 = 45 / 1.2 = 37.5

s = \sqrt{37.5} = 6.124 ft

h = 45/s - 0.6s = 3.674 ft

4 0
4 years ago
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