Solve for x:(2 x + 3)/3 - 1 = 10
Put each term in (2 x + 3)/3 - 1 over the common denominator 3: (2 x + 3)/3 - 1 = (2 x + 3)/3 - (3)/3:(2 x + 3)/3 - (3)/3 = 10
(2 x + 3)/3 - (3)/3 = ((2 x + 3) - 3)/3:(-3 + 3 + 2 x)/3 = 10
Add like terms. 3 - 3 = 0:(2 x)/3 = 10
Multiply both sides of (2 x)/3 = 10 by 3/2:(3×2 x)/(2×3) = (3×10)/2
(3×10)/2 = (3×10)/2:(3×2 x)/(2×3) = (3×10)/2
(3×2 x)/(2×3) = (2×3)/(2×3)×x = x:x = (3×10)/2
10/2 = (2×5)/2 = 5:x = 3×5
3×5 = 15:Answer: x = 15
So we need to solve:
3ˣ⁻¹ = 9ˣ⁺²
To do this, we need to have the same base for both sides of the equation.
So let's go with the base of 3.
3² = 9
3ˣ⁻¹ = (3²)ˣ⁺²
3ˣ⁻¹ = 3²ˣ⁺⁴
Since the bases are the same now, we need to get rid of them and we would get:
x - 1 = 2x + 4
Subtract both sides by 2x:
-x - 1 = 4
Add 1 to both sides:
-x = 5
Divide both sides by -1:
x = -5
Answer: 0.2
Step-by-step explanation:
I just found to answer the question "what 15 divided by 75 means", is to answer the question with a question: How many times does 75 go into 15 and I found it!
Answer:
y = -3x -4
Step-by-step explanation:
A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.
The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.
The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...
3(x+3) +(y-5) = 0
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This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:
3x +9 +y -5 = 0 . . . . . eliminate parentheses
y = -3x -4 . . . . . subtract terms that are not "y"