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3 years ago

HELP ASAP What is the coefficient of the term 6/7xy ?

Mathematics

2 answers:

yawa3891 [41]3 years ago

7 0

Answer: The coefficient of the 6/7xy is 6/7.

ira [324]3 years ago

7 0

Answer:

The coefficient of the term 6/7xy is 6/7

Step-by-step explanation:

, ... A term is combination of variables and numerals by means of multiplication and division.

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A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed

AURORKA [14]

Answer:

A 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Step-by-step explanation:

We are given that Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured.

For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 and For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09.

Firstly, the pivotal quantity for finding the confidence interval for the difference in population mean is given by;

P.Q. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean speed for the 25-mil film = 1.15

$\bar X_1$ = sample mean speed for the 20-mil film = 1.06

$s_1$ = sample standard deviation for the 25-mil film = 0.11

$s_2$ = sample standard deviation for the 20-mil film = 0.09

$n_1$ = sample of 25-mil film = 8

$n_2$ = sample of 20-mil film = 8

$\mu_1$ = population mean speed for the 25-mil film

$\mu_2$ = population mean speed for the 20-mil film

Also, $s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }$ = $\sqrt{\frac{(8-1)\times 0.11^{2}+ (8-1)\times 0.09^{2}}{8+8-2} }$ = 0.1005

Here for constructing a 98% confidence interval we have used a Two-sample t-test statistics because we don't know about population standard deviations.

So, 98% confidence interval for the difference in population means, ( $\mu_1-\mu_2$ ) is;

P(-2.624 < $t_1_4$ < 2.624) = 0.98 {As the critical value of t at 14 degrees of

freedom are -2.624 & 2.624 with P = 1%}

P(-2.624 < $\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < 2.624) = 0.98

P( $-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < $2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ) = 0.98

P( $(\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ) = 0.98

98% confidence interval for ( $\mu_1-\mu_2$ ) = [ $(\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ]

= [ $(1.15-1.06)-2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }$ , $(1.15-1.06)+2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }$ ]

= [-0.042, 0.222]

Therefore, a 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Since the above interval contains 0; this means that decreasing the thickness of the film doesn't increase the speed of the film.

7 0

2 years ago

A rectangular prism is 12 cm long, 6 cm wide, and 5 cm high.

forsale [732]

Answer:

D. 360 cubic cm.

Step-by-step explanation:

The volume = l * w * h

= 12 * 6 * 5

360 cu cm.

7 0

3 years ago

Read 2 more answers

a cone with a radius 3 units is shown below. it’s volume is 57 cubic units. find the height of the cone

ipn [44]

Given:

Given that the radius of the cone is 3 units.

The volume of the cone is 57 cubic units.

We need to determine the height of the cone.

Height of the cone:

The height of the cone can be determined using the formula,

$V=\frac{1}{3} \pi r^2 h$

Substituting the values, r = 3 and V = 57, we get;

$57=\frac{1}{3} (3.14) (3)^2 h$

Simplifying the terms, we get;

$57=\frac{1}{3} (3.14) (9) h$

Multiplying both sides of the equation by 3, we get;

$171= (3.14) (9) h$

$171=28.26 h$

Dividing both sides of the equation by 28.26, we get;

$6.05=h$

Thus, the height of the cone is 6.05 units.

8 0

3 years ago

Help asap will mark brainliest

Harrizon [31]

Answer:

Step-by-step explanation:

7-5

-21-0

-2/21. the y intercept would be 5, considering the x is 0 on the first pair of coordinates. so y=-2/21x+5, or A

8 0

2 years ago

Read 2 more answers

If there are 10 billion transistors (each of a square shape) uniformly (without space) distributed on a silicon chip with the sq

Karo-lina-s [1.5K]

Answer:

the transistors have L=1 mm of linear size

Step-by-step explanation:

For the silicon chip the area is A=1 cm² and for the transistors the area is At=L² (L=linear size) . Then since N= 10 billion transistors of area At should fit in the area A

A=N*At

A=N*L²

solving for L

L= √(A/N)

Assuming that 1 billion=10⁹ (short scale version of billion), then

L= √(A/N) = √(1 cm²/10⁹) = 1 cm / 10³ = 1 mm

then the transistors have L=1 mm of linear size

4 0

3 years ago

HELP ASAP What is the coefficient of the term ​ 6/7xy ​?

HELP ASAP What is the coefficient of the term 6/7xy ?