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3 years ago

Plz i need help i need work too. ALL work

Mathematics

2 answers:

poizon [28]3 years ago

8 0

The picture you posted did not show ?

Levart [38]3 years ago

6 0

There no picture to the post

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One leg of a right triangle is 12, and the hypotenuse is 20.

adoni [48]

We can ise Pythagorean triplet which is ( 12 , 16 , 20 )

Therefore the answer is 16.

Step-by-step explanation:

Or we can use Pythagoras theorem , stated as ;

( hyp )^2 = ( adj )^2 + ( opp )^2

hyp ( hypotenuse ) = 20

We can assume the adj ( adjacent ) = 12

By substituting the values ,

20^2 = 12^2 + ( adj )^2

400 = 144 + ( adj )^2

400 - 144 = ( adj )^2

256 = ( adj )^2

Take the square root of both sides

✓256 = adj

16 = adj

Therefore the length of the other leg which is the adjacent( adj ) side is 16.

8 0

3 years ago

The width of a rectangle is 9 inches less than the length. The perimeter is 38 inches. Find the length and the width.

defon

Answer:

Length: 10

Width: 9

Explanation:

Perimeter Formula:

2(length + width)

So 2(length + width)=38

length + width=19

length + 9=19

length=10

4 0

3 years ago

The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) .

zalisa [80]

-1/3
3
-7
Is
Two have the product of -1

8 0

4 years ago

Read 2 more answers

From Euler’s relation eiθ = cosθ + isinθ,

adelina 88 [10]

Answer:

(a) The graphic representation is in the attached figure.

(b) $\cos(\theta) = \frac{e^{i\theta} + e^{-i\theta}}{2}$ .

(c) $\sin(\theta) = \frac{e^{i\theta} - e^{-i\theta}}{2i}$ .

Step-by-step explanation:

(a) Given a complex number $e^{i\theta}$ we know, from Euler's formula that $e^{i\theta} = \cos(\theta)+i\sin(\theta)$ . So, it is not difficult to notice that

$|e^{i\theta}|^2 = \cos^2(\theta)+\sin^2(\theta) =1$

so it is on the unit circumference. Also, notice that the Cartesian representation of the complex number is $(\cos(\theta), \sin(\theta))$ .

Now,

$e^{-i\theta} = \cos(\theta)+i\sin(-\theta) = \cos(\theta)-i\sin(\theta)$ .

Notice that $e^{-i\theta}$ has the same modulus that $e^{i\theta}$ , so it is on the unit circumference. Beside, its Cartesian representation is $(\cos(\theta), -\sin(\theta))$ .

So, the points $(\cos(\theta), \sin(\theta))$ and $(\cos(\theta), -\sin(\theta))$ are symmetric with respect to the X-axis. All this can be checked in the attached figure.