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Reil [10]
3 years ago
11

Which equation is true? O 1150) = - 150 01 - 150 = 150 - 150 = 150 O-1 - 150= 150

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

THe 3rd equation is true

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I need help pls help
Sauron [17]

Answer:

I could be wrong, but I think it's D

8 0
3 years ago
Which sample size out of a population of 1,000 is most likely to lead to a valid conclusion?
Klio2033 [76]
200, because the more samples you have the more correct you will be.
5 0
3 years ago
Read 2 more answers
He was a newcomer in the land, a chechaquo, and this was his first winter. The trouble with him was that he was without imaginat
Brilliant_brown [7]

Answer:

The author is trying to tell us that you need an imagination

Step-by-step explanation:

4 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
Professor Turner wrote the expression below on the chalkboard for his team at the Research Center. He asked the scientists there
Lynna [10]

Answer:

12x + 18y + 6z + 4x - 4z

Step-by-step explanation:

Given the expression : 3(4x + 6y + 2z) + 4(x – z)

To eliminate the parenthesis ; we use the distributive property :

3(4x + 6y + 2z) + 4(x – z) becomes ;

3*4x + 3*6y + 3*2z + 4*x + 4*-z

12x + 18y + 6z + 4x - 4z

Hence,

12x + 4x + 18y + 6z - 4z

16x + 18y + 2z

6 0
3 years ago
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