A 35 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block ar
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We can visualize the problem in another way, which is equivalent but easier to solve: let's imagine we hold one proton in the same place, and we move the other proton from a distance of 2.00×10−10 m to a distance of 3.00×10−15 m from the first proton. How much work is done?
The work done is equal to the electric potential energy gained by the proton:
where is the charge of the proton and
is the potential difference between the final position and the initial position of the proton. To calculate this
, we must calculate the electric potential generated by the proton at rest at the two points, using the formula:
where is the Coulomb constant and Q is the proton charge. Substituting the initial and final distance of the second proton, we find
Therefore, the work done is