Write an inequality for this situation. You cannot go more than 65 mph on route 18.

How do you do this? conculsion statements.

-Dominant- [34]

Hi,
The conclusion should be letter B, if Karl runs 1mi, then he runs 5280 ft. In fact, that option is the only one in which you combine the information you have to get a conclusion.

5 0

3 years ago

Read 2 more answers

Estimate 22274 divided by 37

emmasim [6.3K]

Answer:

i believe the answer 602

Step-by-step explanation:

tell me if im wrong but hoped I helped:)

5 0

3 years ago

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Team tool bella canoed 15 3/4 miles in 5 1/4 hours. What was their average rate of speed in mph

yarga [219]

Team Tool Bella's average rate was 3 miles per hour.

6 0

3 years ago

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A development economist is studying income growth in a rural area of a developing country. The last census of the population of

kykrilka [37]

Answer:

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.

Step-by-step explanation:

Data given and notation

$\bar X=433.75$ represent the mean height for the sample

$\sigma=\sqrt{2500}=50$ represent the population standard deviation for the sample

$n=100$ sample size

$\mu_o =425$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean height actually is higher than the mean height for men in 1960, the system of hypothesis would be:

Null hypothesis: $\mu \leq 425$

Alternative hypothesis: $\mu > 425$

Since we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{433.75-425}{\frac{50}{\sqrt{100}}}=1.75$

P-value

Since is a one right tail test the p value would be:

$p_v =P(z>1.75)=1-P(z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.

3 0

4 years ago

Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 3 over 2 x +5.

Oliga [24]

We have that

Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = (3/2)x +5

parallel lines are the same slope
then
m=(3/2)

step 1

find the equation of a line with
m=3/2 and point (2,3)

y-y1=m*(x-x1)----------> y-3=(3/2)*(x-2)------> y=(3/2)x

the answer is
y=(3/2)x
y = 3 over 2 x

see the attached figure

8 0

3 years ago