No answer is possible using only the information given in the question.
In addition to the angle of depression, we need either one of these:
-- the length of the tree's shadow on the ground
-- the slant distance direct from the tip of the shadow to the top of the tree.
I'm going out on a limb and guessing that on the page, next to that much of the
question, was a picture of the tree, with one of these additional items labeled.
There's an important reason why the publisher decided to go to the effort and
expense of printing the picture right there. I leave you to ponder the reason.
T(1)=.46 sec
T(2)= 11.72 sec
The ratio of length to width is 9:11 is to 9 as x is to 40.41/9 = x/40.4 x = 40.4/9 = 4.48888.. meters
Answer: The toy should be 2.4 inches tall
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Explanation:
First convert 6 ft to inches
6 ft = (6 ft)*(12 in/1 ft) = (6*12) inches = 72 inches
So, 6 ft = 72 inches
The toy is manufactured with a scale of 1:30 meaning that the toy is 1 unit tall compared to the soldier which is 30 units tall. The soldier is 30 times taller than the toy. We can therefore form the ratio
1/30 = x/72
where x is the height of the toy soldier in inches
Cross multiply and solve for x
1/30 = x/72
1*72 = 30*x
72 = 30*x
72/30 = 30*x/30
72/30 = x
x = 72/30
x = 12/5
x = 2.4
So the toy should be 2.4 inches tall.
Note how 30 times 2.4 gives us
30*2.4 = 72
which fits with the theme that the real soldier is 30 times taller than the toy counter part.
