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emmasim [6.3K]
3 years ago
9

Which property is being used here? 5.2345 x 1 = 5.2345

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
Multiplication not to sure hope this helps :)
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Can someone please help me
bogdanovich [222]
Sent a picture of the solution to the problem (s).

4 0
4 years ago
Tiffany sees this given dilation and claims that the scale factor is 2
Alenkinab [10]

Answer:

The scale factor is not 2

Step-by-step explanation:

Given

See attachment for the dilated triangles

Triangle ABC is dilated through center point O to form triangle A'B'C'.

From the attachment, we have:

OC = 2 i.e. the distance from the center point to C

and

OC' = 6 i.e. the distance from the center point to C'

The length of OC' is calculated using:

OC' = OC + CC'

OC' = 2 + 4

OC' = 6

The scale factor (k) is then calculated by dividing OC' by OC

k = \frac{OC'}{OC}

k = \frac{6}{2}

k = 3

Hence, Tiffany's claim is incorrect.

5 0
3 years ago
PLEASE HELP A flight across the US takes longer east to west then it does west to east. This is due to the plane having a headwi
il63 [147K]
To solve our questions, we are going to use the kinematic equation for distance: d=vt
where
d is distance 
v is speed  
t is time 

1. Let v_{w} be the speed of the wind, t_{w} be time of the westward trip, and t_{e} the time of the eastward trip. We know from our problem that the distance between the cities is 2,400 miles, so d=2400. We also know that the speed of the plane is 450 mi/hr, so v=450. Now we can use our equation the relate the unknown quantities with the quantities that we know:

<span>Going westward:
The plane is flying against the wind, so we need to subtract the speed of the wind form the speed of the plane:
</span>d=vt
2400=(450-v_{w})t_{w}

Going eastward:
The plane is flying with the wind, so we need to add the speed of the wind to the speed of the plane:
d=vt
2400=(450+v_{w})t_{e}

We can conclude that you should complete the chart as follows:
Going westward -Distance: 2400 Rate:450-v_w Time:t_w
Going eastward -Distance: 2400 Rate:450+v_w Time:t_e

2. Notice that we already have to equations:
Going westward: 2400=(450-v_{w})t_{w} equation(1)
Going eastward: 2400=(450+v_{w})t_{e} equation (2)

Let t_{t} be the time of the round trip. We know from our problem that the round trip takes 11 hours, so t_{t}=11, but we also know that the time round trip is the time of the westward trip plus the time of the eastward trip, so t_{t}=t_w+t_e. Using this equation we can express t_w in terms of t_e:
t_{t}=t_w+t_e
11=t_w+t_e equation
t_w=11-t_e equation (3)
Now, we can replace equation (3) in equation (1) to create a system of equations with two unknowns: 
2400=(450-v_{w})t_{w}
2400=(450-v_{w})(11-t_e) 

We can conclude that the system of equations that represent the situation if the round trip takes 11 hours is:
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

3. Lets solve our system of equations to find the speed of the wind: 
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

Step 1. Solve for t_{e} in equation (2)
2400=(450+v_{w})t_{e}
t_{e}= \frac{2400}{450+v_{w}} equation (3)

Step 2. Replace equation (3) in equation (1) and solve for v_w:
2400=(450-v_{w})(11-t_e)
2400=(450-v_{w})(11-\frac{2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{4950+11v_w-2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{255011v_w}{450+v_{w}} )
2400= \frac{1147500+4950v_w-2550v_w-11(v_w)^2}{450+v_{w}}
2400(450+v_{w})=1147500+2400v_w-11(v_w)^2
1080000+2400v_w=1147500+2400v_w-11(v_w)^2
(11v_w)^2-67500=0
11(v_w)^2=67500
(v_w)^2= \frac{67500}{11}
v_w= \sqrt{\frac{67500}{11}}
v_w=78

We can conclude that the speed of the wind is 78 mi/hr.
6 0
3 years ago
Hello, can anyone explain the steps to solve these questions, please? Thanks!
Llana [10]

Answer:

56776h

Step-by-step explanation:

i did it

7 0
2 years ago
A tape diagram. There are 65 students out of 100 students who ride the bus. There are question mark students out of 800 students
SVEN [57.7K]

Answer:

<em>800÷100 = 8</em>

<em>65×8=520</em>

\frac{520}{800}

another way:

<em>100%-65%=35%</em>

<em>35% = 0.35</em>

<em>800×0.35= 280</em>

<em>800-280=</em>520

another way:

<em>65% = 0.65</em>

<em>0.65×800=</em>520

Hope it helped! :)

6 0
2 years ago
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