The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
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Answer:
A, B, and C
Step-by-step explanation:
The discriminant is denoted by b^2 - 4ac, and it can give us information about the roots of the quadratic equation.
It tells us that if:
- b^2 - 4ac < 0 , then there are 0 real solutions; they're all imaginary (involving the letter i, which is the square root of -1)
- b^2 - 4ac = 0 , then there is 1 real solution; this 1 solution has a multiplicity of 2 because the roots of the quadratic are the same number
- b^2 - 4ac > 0 , then there are 2 real solutions; there are no imaginary solutions
Looking at the possible choices, we see that all of A (A, I'm assuming you meant to write "if the discriminant is zero there is one real solution"), B, and C reflect the above properties.
Thus, they're all right.
Answer: 2 sticks.
Step-by-step explanation:
Given statement: You need 3 sticks of butter for every 24 cookies you bake.
Using unitary method , the number of sticks of butter used to bake 1 cookie=
Then the number of sticks of butter used to bake 1 cookie=
Hence, the number of sticks of butter used to bake 16 cookies= 2
