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ahrayia [7]
2 years ago
8

The first month a company was open, it had 2 employees. At the end of 6 months, the company had 10 employees. If the number of e

mployees increases at a steady rate, write an equation that illustrates this situation.​
Mathematics
1 answer:
deff fn [24]2 years ago
4 0

the equation would be 2[6]+10 however if we were to solve it would have been 2(6)+10 = 22 employees

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A large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and
scoundrel [369]

Answer:

-6.134 to +6.134

Step-by-step explanation:

given that a large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and a normal distribution

X is Normal with mean  =6.1 and std dev = 1 unit

We are to determine the range of values containing 70% of the population of x

We know that normal distribution curve is bell shaped symmetrical about the mean.

So to find 70% range we can use 35% on either side of the mean

Using std normal distribution table the value of z for which probability from 0 to z is 0.35 is 1.034

Hence corresponding x value is

x=6.1+1.034*1\\x=6.134

i.e. 70% values lie between

-6.134 to +6.134

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3 years ago
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8 0
2 years ago
Mia and John are selling boxes of apples. They have small boxes and large boxes. Mia sells 6 small boxes and 2 large boxes for a
kvasek [131]

so

6s+2l = 28

4s+5l=  37

eliminate 6s+2l=28 by dividing all numbers by 6

u get s= -1/3 l + 14/3

49-1/3l=14/3) + 5l =37

L=5

s= -1/3(5) + 14/3

s=3

l=5

     

6 0
3 years ago
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if clare goes to the bank every 7 days and clare go's to the bank every 5 days what day will they bolth go to the bank
d1i1m1o1n [39]
The weekdays
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7 0
2 years ago
determine the value of m and n for mx^3 +20x^2+ nx-36 when divided by (x+1) gives remainder 0 and when divided by (x-2) gives re
soldi70 [24.7K]

Given:

The given polynomial is

mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0 and when divided by (x-2) gives remainder of 45.

To find:

The values of m and n.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

Let the given polynomial be P(x).

P(x)=mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0. So, P(-1)=0.

P(-1)=m(-1)^3+20(-1)^2+n(-1)-36

0=-m+20-n-36

0=-m-n-16

m+n=-16                   ...(i)

When P(x) is divided by (x-2) gives remainder of 45. So, P(2)=0

m(2)^3+20(2)^2+n(2)-36=45

8m+80+2n-36=45

8m+2n+44=45

8m+2n=45-44

8m+2n=1                  ...(ii)

Multiply 2 on both sides of (i).

2m+2n=-32                   ...(iii)

Subtract (iii) from (ii).

6m=33

m=\dfrac{33}{6}

m=5.5

Putting m=5.5 in (i), we get

5.5+n=-16

n=-16-5.5

n=-21.5

Therefore, the values of m and n are 5.5 and -21.5 respectively.

7 0
3 years ago
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