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Zepler [3.9K]
3 years ago
9

Jace’s basketball team scored 38 points in the first game of the season. In the next two games they scored a total of 77 points.

For every point scored, $0.50 is put in a jar to use for a party after the season. Jace says that you can use the expression 38 +77 x 0.5 to find how much money is in the jar after the third game. help me plz
Part 1: Is he correct?



Part 2: How do you know? Please explain your answer





help now
Mathematics
2 answers:
NemiM [27]3 years ago
7 0

Answer:

yes he is correct

Step-by-step explanation:

because first you add 38 + 77 =115 and then you multiply by 0.5, so 115 times 0.5 = 57.5

tia_tia [17]3 years ago
3 0

Answer:

Jace is wrong

This how you do it: (19 + 77 x (0.5) )

Step-by-step explanation:

Here, for each point scored, $0.5 is put in the jar.

Now, the point scored in the first game  = 38 points

So, the amount put in the jar for 38 points = 38 x ( amount for 1 point)

=  38 x ( $0.5)   = $19

So, after first game, jar has $19.

Now, the point scored in the(2 +3) game  = 77 points

So, the amount put in the jar for 77 points = 77 x ( amount for 1 point)=  77 x ( $0.5)   = 77 x (0.5)

So, after second and third  game, jar has $ (77 x (0.5)).

Now, total amount in jar  

= Amount after first game  + Amount after second and third game

= 19 + 77 x (0.5)

But , here THE TOTAL AMOUNT given by Jace  = 38+(77  x 0.5)

And 19 + 77 x (0.5)  ≠ 38+(77  x 0.5)

$57.5

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Assume that SAT scores are normally distributed with mean 1518 and standard deviation 325. Round your answers to 4 decimal place
Katyanochek1 [597]

Answer:

a. 0.2898

b. 0.0218

c. 0.1210

d. 0.1515

e. This is because the population is normally distributed.

Step-by-step explanation:

Assume that SAT scores are normally distributed with mean 1518 and standard deviation 325. Round your answers to 4 decimal places

We are using the z score formula when random samples

This is given as:

z = (x-μ)/σ/√n

where x is the raw score

μ is the population mean

σ is the population standard deviation.

n is the random number of samples

a.If 100 SAT scores are randomly selected, find the probability that they have a mean less than 1500.

For x = 1500, n = 100

z = 1500 - 1518/325/√100

z = -18/325/10

z = -18/32.5

z = -0.55385

Probability value from Z-Table:

P(x<1500) = 0.28984

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b. If 64 SAT scores are randomly selected, find the probability that they have a mean greater than 1600

For x = 1600, n = 64

= z = 1600 - 1518/325/√64.

z= 1600 - 1518 /325/8

z = 2.01846

Probability value from Z-Table:

P(x<1600) = 0.97823

P(x>1600) = 1 - P(x<1600) = 0.021772

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c. If 25 SAT scores are randomly selected, find the probability that they have a mean between 1550 and 1575

For x = 1550, n = 25

z = 1550 - 1518/325/√25

z = 1550 - 1518/325/5

z = 1550 - 1518/65

= 0.49231

Probability value from Z-Table:

P(x = 1550) = 0.68875

For x = 1575 , n = 25

z = 1575 - 1518/325/√25

z = 1575 - 1518/325/5

z = 1575 - 1518/65

z = 0.87692

Probability value from Z-Table:

P(x=1575) = 0.80974

The probability that they have a mean between 1550 and 1575

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= 0.80974 - 0.68875

= 0.12099

Approximately = 0.1210

d. If 16 SAT scores are randomly selected, find the probability that they have a mean between 1440 and 1480

For x = 1440, n = 16

z = 1440 - 1518/325/√16

= -0.96

Probability value from Z-Table:

P(x = 1440) = 0.16853

For x = 1480, n = 16

z = 1480 - 1518/325/√16

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Probability value from Z-Table:

P(x = 1480) = 0.32

The probability that they have a mean between 1440 and 1480

P(x = 1480) - P(x = 1440)

= 0.32 - 0.16853

= 0.15147

Approximately = 0.1515

e. In part c and part d, why can the central limit theorem be used even though the sample size does not exceed 30?

The central theorem can be used even though the sample size does not exceed 30 because the population is normally distributed.

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