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2 years ago

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Help pls I will give brainliest! 6

1 answer:

VashaNatasha [74]2 years ago

5 0

Answer:

8. 822

9. 1582

10. 1936

11. 8200

Step-by-step explanation:

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Find the volume of a cylinder that has a diameter of 12 in. and a height of 15 in

daser333 [38]

Answer:

<h3> $\sf{ \boxed{ \bold{1697.14}}}$ </h3>

Step-by-step explanation:

Given,

diameter ( d ) = 12 in

height ( h ) = 15 in

<u>finding </u><u>the </u><u>radius </u><u>of </u><u>a </u><u>cylinder</u>

Radius is just half of diameter.

Radius ( r ) = 12 / 2 = 6 in

<u>finding </u><u>the </u><u>volume </u><u>of </u><u>a </u><u>cylinder </u><u>having </u><u>radius </u><u>of </u><u>6</u><u> </u><u>in </u><u>and </u><u>height </u><u>of </u><u>1</u><u>5</u><u> </u><u>in</u>

Volume of a cylinder = <u> $\sf{\pi \: {r}^{2} h}$ </u>

⇒ $\sf{ \frac{22}{7} \times {6}^{2} \times 15}$

⇒ $\sf{ \frac{22}{7} \times 36 \times 15}$

⇒<u> $\sf{1697.14} \: in$ </u>

Hope I helped!

Best regards!!

6 0

3 years ago

Read 2 more answers

Approximate the value of 51. helepepe

Mrrafil [7]

Answer:

slightly more than 15

Step-by-step explanation:

5 0

2 years ago

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How do I simplify the expression 4p-5(p+6)

pochemuha

4p - 5p - 30 = -1p - 30

7 0

2 years ago

Read 2 more answers

Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A = {1, 3, 5, 7, 9}, B = {2, 4, 6, 8, 10}, and C = {1, 2, 4, 5, 8, 9}. List the element

Leto [7]

Answer:

$C\ n\ C^c = \{ \}$

$(A\ n\ C)^c = \{2,3,4,6,7,8,10\}$

$A\ u\ (B\ n\ C) = \{1, 2,3, 4,5, 7, 8,9\}$

Step-by-step explanation:

Required

Determine

$C\ n\ C^c$

$(A\ n\ C)^c$

$A\ u\ (B\ n\ C)$

Solving $C\ n\ C^c$

$C^c$ implies that elements in U but not in C

Since

$C = \{1, 2, 4, 5, 8, 9\}$

$C^c = \{3, 6, 7, 10\}$

$C\ n\ C^c = \{1, 2, 4, 5, 8, 9\}\ n\ \{3, 6, 7, 10\}$

$C\ n\ C^c = \{ \}$

<em>Because there's no intersection between both</em>

Solving $(A\ n\ C)^c$

First, we need to determine A n C

$A\ n\ C = \{1, 3, 5, 7, 9\}\ n\ \{1, 2, 4, 5, 8, 9\}$

$A\ n\ C = \{1, 5, 9\}$

$(A\ n\ C)^c = (\{1, 5, 9\})^c$

$(A\ n\ C)^c = \{2,3,4,6,7,8,10\}$

Solving $A\ u\ (B\ n\ C)$

First, we need to determine B n C

$B\ n\ C = \{2, 4, 6, 8, 10\}\ n\ \{1, 2, 4, 5, 8, 9\}$

$B\ n\ C = \{2, 4, 8\}$

So:

$A\ u\ (B\ n\ C) = \{1, 3, 5, 7, 9\}\ u\ \{2,4,8\}$

$A\ u\ (B\ n\ C) = \{1, 2,3, 4,5, 7, 8,9\}$

4 0

3 years ago

Goshia [24]

Answer:

Option b.

$4x^3y^2\sqrt[3]{4xy}$

Step-by-step explanation:

we have the expression

$\sqrt[3]{256x^{10}y^{7}}$

Remember these properties

$\sqrt[n]{x^m} =x^{\frac{m}{n}}$

$(x^{m})^{n} =x^{m*n}$

$(x^{m})(x^{n})=x^{m+n}$

so

$\sqrt[3]{256x^{10}y^{7}}=(256x^{10}y^{7})^{\frac{1}{3}}=(256^{\frac{1}{3}})(x^{\frac{10}{3}})(y^{\frac{7}{3}})$

Rewrite the expression

$256=(4^3)(2^2)$

$x^{10}=(x^9)(x)$

$y^7=(y^6)(y)$

substitute

$(256x^{10}y^{7})^{\frac{1}{3}}=((4^3)(2^2)(x^9)(x)(y^6)(y))^{\frac{1}{3}}$

Applying properties of exponents

$((4^3)(2^2)(x^9)(x)(y^6)(y))^{\frac{1}{3}}=(4^3)^{\frac{1}{3}}(2^2)^{\frac{1}{3}}(x^9)^{\frac{1}{3}}(x)^{\frac{1}{3}}(y^6)^{\frac{1}{3}}(y)^{\frac{1}{3}}$

simplify

$(4)^{\frac{3}{3}}(2)^{\frac{2}{3}}(x)^{\frac{9}{3}}(x)^{\frac{1}{3}}(y)^{\frac{6}{3}}(y)^{\frac{1}{3}}$

$(4)(2)^{\frac{2}{3}}(x)^{3}(x)^{\frac{1}{3}}(y)^{2}(y)^{\frac{1}{3}}$

$4x^3y^2\sqrt[3]{4xy}$

6 0

2 years ago

Read 2 more answers