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White raven [17]
2 years ago
14

Which of the following factors is likely to have a positive impact on the success of a TQM program? Check all that apply. Employ

ees work at tasks that require high skills. Continuous improvement becomes a way of life. Managers expect to see dramatic innovations as a result of TQM. Employees use participation and teamwork to tackle significant problems.
Business
1 answer:
irakobra [83]2 years ago
7 0

Answer:

continued improvement.allows consistent tqm

You might be interested in
If the liabilities of a business increased $75,000 during a period of time and the owner's equity in the business decreased $30,
GrogVix [38]

Answer:

D. Increased $45,00

Explanation:

Assume that the total assets of the business was $100,000 and the liabilities was $50,000 and the equity was also $50,000.These figures can be expressed in terms of the accounting equation as follows:

Total assets=Total liabilities+Total equity

100,000=50,000+50,000

Now consider that the above mentioned liabilities are increased by $75,000 as stated in question and above mentioned equity is decreased by $30,000 as stated in question, then the assets as per accounting equation can be determined as follows:

Total liabilities=50,000+75,000=$125,000

Total equity=50,000-30,000=$20,000

Assets=$125,000+$20,000=145,000

Total increase in assets=$145,000-$100,000=$45,000

So the answer is D. Increased $45,000

6 0
3 years ago
The following costs were incurred in May:
galben [10]

Answer:

the conversion cost is $58,200

Explanation:

The computation of the conversion cost is shown below:

The conversion cost is

= Direct Labor + Manufacturing Overhead

= $32,800 + $25,400

= $58,200

Hence, the conversion cost is $58,200

It is the combination of the direct labor and the manfacturing overhead

6 0
3 years ago
The assets of Dallas & Associates consist entirely of current assets and net plant and equipment, and the firm has no excess
OlgaM077 [116]

Answer:

Explanation:

1.Total Debt = Total Assets – Total Equity  = 2,700,000 – 1,550,000

= $1,150,000

2.Total assets = Total liabilities +Total equity = $2,700,000

3.Current Assets = Total Assets – Plant and Equipment  = 2,700,000-2,300,000  = 400,000

4.Current Liabilities = Total Liabilities – Long term debt = 1,150,000 – 748,000  = $402000

5.Accounts payables and accruals = current liabilities – notes payables

= 402000  – 150,000  = $252000

6.Working capital = Current Assets – Current Liabilities  = 400,000-402,000

= -2000

7.Net operating working capital = Current assets – Accounts payables and accruals  = 400,000 – 252,000  = 148,000

8.Difference = -2,000-148,000 = -150,000  (indicates note payable)

Recalculation with new information:

1.Total Debt = Total Assets – Total Equity  = 4,000,000 – 2,000,000 -500,000 =  

= $1,500,000

2.Total assets = Total liabilities +Total equity = $4,000,000

3.Current Assets = Total Assets – Plant and Equipment  = 4,000,000-3,000,000  = $1,000,000

4.Current Liabilities = Total Liabilities – Long term debt = 1,500,000 – 950,000  = $550000

5.Accounts payables and accruals = current liabilities – notes payables

= 550,000  – 150,000  = $400,000

7 0
3 years ago
In ____ price discrimination, the monopolist charges each consumer the highest price that purchaser is willing to pay for each u
Advocard [28]

Answer:

Perfect price discrimination

Explanation:

Perfect price discrimination or first degree discrimination is defined as one in which the maximum price possible is charged for each unit of product sold to the customer.

This is aimed at capturing all consumer surplus for the monopoly.

This can occur for example in cases where the zip code of clients is located in an area where wealthy people reside.

The monopolist can charge the highest possible price based on the location.

6 0
3 years ago
A metal sphere of radius 15 cm has a net charge of 3.0 $ 10#8 C. (a) What is the electric field at the sphere’s surface? (b) If
denis-greek [22]

Answer:

E = 1.20 × 10^{4} N/C

V = 1800 V

x = 0.058 m

Explanation:

given data

radius = 15 cm

net charge = 3 × 10^{-8} C

electric potential decreased = 500 V

solution

we get here electric field at the sphere’s surface that is

electric field at the sphere’s surface E  =  \frac{q}{4\pi \epsilon _o R^2}   ............1

put here value

electric field at the sphere’s surface E  = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15^2}    

E = 1.20 × 10^{4} N/C

and

potential on surface of sphere is

V =  \frac{q}{4\pi \epsilon _o R} ................2

V = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15}  

V = 1800 V

and

now we get distance that is x

and we know here

ΔV = V(x) - V   ..............3

substitute here value

-500V = \frac{q}{4\pi \epsilon _o } \times (\frac{1}{R+x} - \frac{1}{R})

-500 V = {3\times 10^{-8}\times 8.99\times 10^9} \times (\frac{1}{0.15+x} - \frac{1}{0.15})

solve it we get x

x = 0.058 m

3 0
3 years ago
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