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dusya [7]
3 years ago
10

Help me please it’s due soon

Mathematics
1 answer:
prisoha [69]3 years ago
8 0

The solution is negative.

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which equation models the same quadratic relationship as function f? f(x)=x^2+12x+4 a) y=(x-6)^2+40 b) y=(x+6)^2-32 c) y=(x-6)^2
motikmotik

9514 1404 393

Answer:

  b) y=(x+6)^2-32

Step-by-step explanation:

Add and subtract the square of half the x-coefficient to put into vertex form.

  f(x) = x^2 +12x +4 . . . . . given

  y = x^2 +12x +36 +4 -36 . . . . add and subtract (12/2)^2 = 36

  y = (x +6)^2 -32 . . . . . . . . . . . write in vertex form

7 0
2 years ago
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Mr. Hudkins wants his 6th grade math class to memorize their multiplication facts. He decides to increase the number of facts th
Maksim231197 [3]

Answer: m = 15w

Step-by-step explanation: The reason why the answer is m = 15w is because since he said "He decides to increase the number of facts they are expected to memorize each week." Which makes it so that only the  multiplication fact increased to 15 since they wouldn't put it lower then that. And there is a 2nd reason why the multiplication fact is 15. the reason why is because theres only one answer with 30 and its completely wrong. So therefore,, The answer is Multiplication Fact = 15weeks.

8 0
3 years ago
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Will mark brainliest, pls explain!!
alukav5142 [94]

Answer:

  • B-Neither ordered pair is a solution.

Step-by-step explanation:

<h3>Given</h3>

<u>Equation </u>

  • 6x−y^2=14

<u>Ordered pairs </u>

  • (−9,3) and (2,−4)
<h3>Verifying pairs</h3>

(−9,3)

  • 6(-9) - 3^2 = 14
  • -54 - 9 = 14
  • -63 = 14
  • Incorrect

(2,−4)

  • 6(2) - (-4)^2 = 14
  • 12 - 16 = 14
  • -4 = 14
  • Incorrect

Correct option is B

6 0
3 years ago
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The scale of a map says that 2 cm represents 8 km. What is the actual number of kilometers that is represented by 3 centimeters
wolverine [178]
12kilometers
If 2cm=8km, 1cm=4km
Multiply both by three and you get that 3cm=12km
3 0
3 years ago
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May I please receive help?
ruslelena [56]

Answer:

so you have to find angles

5 0
3 years ago
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