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damaskus [11]
3 years ago
7

What is the density of an object with a mass of 140 g and a volume of 6 ml

Chemistry
1 answer:
Strike441 [17]3 years ago
5 0

Answer:

<h2>23.33 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{140}{6} =  \frac{70}{3}   \\  = 23.3333...

We have the final answer as

<h3>23.33 g/mL</h3>

Hope this helps you

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In what type of environment would you most likely find Fish Species 1? Explain your answer.
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Fish are more likely to hold a soft bait longer. ... Signs of small fish activity can lead you to fishing hot spots. ... Cover can be loosely defined as anything that will hide or protect the fish.

Explanation:

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An atom or ion has 41 neutrons, 36 protons, and 36 electrons. Identify the clement symbol, and determine the mass
Paul [167]

The atom is krypton and its symbol is Kr.

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3 years ago
In the equation. C + O2 --------&gt; CO2; CO2 is the
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Answer: Product

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                             reactant------> product

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3 years ago
A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli
vladimir1956 [14]

Answer:

109.09°C

Explanation:

Given that:

the capacity of the cooling car system = 5.6 gal

volume of solute = volume of the water; since a 50/50 blend of engine coolant and water (by volume) is used.

∴ \frac{5.60}{2}gallons = 2.80 gallons

Afterwards, the mass of the solute and the mass of the water can be determined as shown below:

mass of solute = (M__1}) = Density*Volume

                          = 1.1g/mL *2.80*\frac{3785.41mL}{1gallon}

                         = 11659.06grams

On the other hand; the mass of water = (M__2})= Density*Volume

                         = 0.998g/mL *2.80*\frac{3785.41mL}{1gallon}

                        = 10577.95 grams

Molarity = \frac{massof solute*1000}{molarmassof solute*massofwater}

              =  \frac{11659.06*1000}{62.07*10577.95}

              = 17.757 m

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\Delta T_{boiling} = k_{boiling}M

where,

k_{boiling} = 0.512 °C/m

\Delta T_{boiling} =  100°C + 17.56 × 0.512

              = 109.09 °C

6 0
3 years ago
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