Answer:
4000 L
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial volume (V1) = 2000 L.
Initial temperature (T1) = 100 K.
Initial pressure (P1) = 100 kPa.
Final temperature (T2) = 400 K.
Final pressure (P2) = 200 kPa.
Final volume (V2) =..?
Step 2:
Determination of the new volume of the gas.
The new volume of the gas can be obtained by using the general gas equation as follow:
P1V1/T1 = P2V2/T2
100 x 2000/100 = 200 x V2/400
Cross multiply to express in linear form.
100 x 200 x V2 = 100 x 2000 x 400
Divide both side by 100 x 200
V2 = (100 x 2000 x 400)/(100 x 200)
V2 = 4000 L
Therefore, the new volume of the gas is 4000 L
1 miles = 1609.344 m
1 hour = 60 min x 60 sec = 3600 s
30 miles 1 hr 1609.344 m
_______ x ______ x __________= 13.412m/s
1 hr 3600 s 1 miles
Answer:
The answer to your question is:
Vol of NO2 = 11.19 L
Vol of O2 = 2.8 L
Explanation:
Data
N2O5 = 56 g
STP T = 0°C = 273°K
P = 1 atm
MW N2O5 = 216 g
Gases law = PV = nRT
Process
216 g of N2O5 ---------------- 1 mol
54 g ----------------- x
x = (54 x 1) / 216
x = 0.25 mol of N2O5
2 mol of N2O5 ----------------- 4 mol of NO2
0.25 mol ------------------ x
x = (0.25 x 4) / 2 = 0.5 mol of NO2
V = nRT/P
V = (0.5)(0.082)(273) / 1 = 11.19 L
2 mol of N2O5 ----------------- 1 O2
0.25 N2O5 ---------------------- x
x = (0.25 x 1) / 2 = 0.125 mol
Vol = (0.125)((0.082)(273) / 1 = 2.8 L
The correct answer is D. Elements are created that differ from the reactants.. Because in a eeaction, the product is different than the reactants. Take NaCl for example.