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sergey [27]
2 years ago
5

How is enthalpy related to the spontaneity of a reaction?

Chemistry
1 answer:
mina [271]2 years ago
5 0

Answer:

D

Explanation:

Gibb's free energy change(∆G) and Standard electrode potential of electrochemical (Ecell) determine the spontaneity of a reaction.

when ∆G > 0, the reaction is not spontaneous

∆G < 0, the reaction is spontaneous

∆G = 0, the reaction is in equilibrium

when Ecell > 0, the redox reaction is spontaneous

Ecell < 0, the redox reaction is not spontaneous

Ecell = 0, the redox reaction is in equilibrium.

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What other kinds of empirical evidence can be used to show common ancestry among organisms?
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Answer:There are, however, other forms of empirical evidence that support the theory of evolution. The fossil record, anatomical and embryological homologous, and genetic similarities are also used to support the theory of evolution. Many pieces of evidence support the theory that birds and dinosaurs are related.

Explanation:hope i am helpful

4 0
3 years ago
Which statement best describes a solution? A). a mixture consisting of minute particles suspended in a medium that start moving
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3 years ago
What is Carbons position on the Periodic table?
MrRissso [65]
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7 0
3 years ago
Examine the equation.
Alisiya [41]

Explanation:

The reaction expression is given as;

                 2H₂_{g}   +  O₂_{g}   →   2H₂O_{l}

From the balance reaction expression:

 2 mole of hydrogen gas combines with 1 mole of oxygen gas on the reactant side;

This produces 2 mole of water on the product side of the expression.

The product is in liquid form.

 This reaction is a synthesis reaction because a single product is formed from two reactants.

5 0
2 years ago
A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mas
Anna71 [15]

Answer:

\large \boxed{\text{528.7 g} }

Explanation:

It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"  

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:                      32.00

              2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ

n/mol:                                                                  7280

1. Moles of O₂

The molar ratio is 25 mol O₂:11 018 kJ

\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}

2. Mass of O₂

\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}

3 0
3 years ago
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