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WARRIOR [948]
3 years ago
7

Dust particles enter the atmosphere when wind picks them up off the ground and carries the upward.

Chemistry
1 answer:
goldfiish [28.3K]3 years ago
6 0
The statement seems to be true, as per my knowledge.

Hope I helped!! xx
You might be interested in
2NH.
liq [111]

Answer:

N=2

H=6

Explanation:

1.Balance a chemical equation in terms of moles.

2.Use the balanced equation to construct conversion factors in terms of moles.

3.Calculate moles of one substance from moles of another substance using a balanced chemical equation.

The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products.

(P.s it could also be where you have to solve it in which you have to simplify it first then solve it.) like adding them all up.

Hope this is the answer. :)

6 0
3 years ago
A 0.216 g sample of carbon dioxide, CO2, has a volume of 507 mL and a pressure of 470 mmHg. What is the temperature of the gas i
Gala2k [10]

Answer:

The temperature of the gas is 876.69 Kelvin

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 470 mmHg
  • V= 570 mL= 0.570 L
  • n= 0.216 g= 0.0049 moles (being the molar mass of carbon dioxide is 44 g/mole)
  • R= 62.36367 \frac{mmHg*L}{mol*K}
  • T=?

Replacing:

470 mmHg*0.570 L= 0.0049 moles* 62.36367 \frac{mmHg*L}{mol*K} *T

Solving:

T=\frac{470 mmHg*0.570 L}{0.0049 moles* 62.36367\frac{mmHg*L}{mol*K} }

T= 876.69 K

<em><u>The temperature of the gas is 876.69 Kelvin</u></em>

6 0
2 years ago
Topics: Fundamentals of electrochemistry; Electrochemical cells
irina1246 [14]

Answer:

how to help people that helps

5 0
2 years ago
If the pressure, volume, and temperature of a gas are known, which can most likely be found by using the ideal gas law?
alukav5142 [94]

Answer:

the moral amount of the gas.

5 0
2 years ago
HELP WHAT IS THE ANSWER TO ANY OF THESE !!!
photoshop1234 [79]
Number 4 is
-Oxidation occurs at the anode, while reduction occurs at the cathode. Recharging a battery involves the conversion of electrical energy to chemical energy. During recharging, there is movement of electrons from an external power source to the anode, and on the other side electrons are removed from the cathode.
8 0
3 years ago
Read 2 more answers
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