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2 years ago

Using the paths shown, the distance from Brookfield to Seaside is 20.4 kilometers.

Mathematics

1 answer:

stepan [7]2 years ago

7 0

Answer:

7.2 km

Step-by-step explanation:

Distance between Brookfield to Seaside = 20.4 km

Distance between Yardley and Seaside = 13.2 km

Let distance between Brookfield to Yardley be x.

Thus:

x + 13.2 km = 20.4 km

Subtract 13.2 from each side

x = 20.4 - 13.2

x = 7.2

Distance from Brookfield to Yardley is 7.2 km

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(x + 4) mm <br> What is the value of x according to this picture?

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Answer:

x = 24

Step-by-step explanation:

The angle bisector creates proportional corresponding line segments on either side of it. That is ...

(35 mm)/(56 mm) = (x +4) mm/(44.8 mm)

Multiplying by 44.8, you have

44.8 · (35/56) = x + 4

28 = x + 4 simplify

24 = x subtract 4

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2 years ago

A piece of climbing equipment at a playground is 6 feet high and extends 4 feet horizontally. A piece of climbing equipment at a

Varvara68 [4.7K]

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Explanation:

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3 years ago

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olga55 [171]

Step-by-step explanation:

a= 1/3

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3 years ago

Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel. How old is Daniel now?

Radda [10]

Answer:

Kevin is 6 years old and Daniel is 3 years old

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They are now 3 years apart but two years ago, they were 4 and 1 years old, so Kevin was 4 times older than.

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3 years ago

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Ket [755]

The area of the house is the amount of space on the house.

The length of the addition is x + 20
The area of the original house is $x^2 + 30x + 200$

<h3>The length of the addition</h3>

The area of the addition is given as:

$Area = x^2 + 10x - 200$

Expand

$Area = x^2 + 20x - 10x - 200$

Factorize

$Area = x(x + 20) - 10(x + 20)$

Factor out x + 20

$Area = (x -10)(x + 20)$

The width of the addition is x - 10.

Hence, the length of the addition is x + 20

<h3>The area of the original house</h3>

The dimension of the original house is

x + 20 by x + 10

So, the area is:

$Area =(x + 20)(x + 10)$

Expand

$Area =x^2 + 20x + 10x + 200$

This gives

$Area =x^2 + 30x + 200$

Hence, the area of the original house is $x^2 + 30x + 200$