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kakasveta [241]
3 years ago
15

Using the paths shown, the distance from Brookfield to Seaside is 20.4 kilometers.

Mathematics
1 answer:
stepan [7]3 years ago
7 0

Answer:

7.2 km

Step-by-step explanation:

Distance between Brookfield to Seaside = 20.4 km

Distance between Yardley and Seaside = 13.2 km

Let distance between Brookfield to Yardley be x.

Thus:

x + 13.2 km = 20.4 km

Subtract 13.2 from each side

x = 20.4 - 13.2

x = 7.2

Distance from Brookfield to Yardley is 7.2 km

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Read 2 more answers
1. Write a rule that will take the triangle to a congruent triangle. Write your rule as (x,y)
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Transforming a shape involves changing the size and/or the location of the shape.

  • The rule that will take the triangle to a congruent triangle is (x,y) \to (x,-y)
  • The rule that will take the triangle to a figure that is similar is (x,y) \to (0.5x,0.5y).
  • The rule that will take the triangle to a figure that is not similar or congruent is (x,y) \to (0.5x,2y).

<h3>Rigid transformation</h3>

When a shape is transformed by a rigid transformation, then the image of the shape will be congruent to the original shape.

An example of a rigid transformation is a reflection over the x-axis; and the rule is:

(x,y) \to (x,-y)

So, a rule that will take the triangle to a congruent triangle is (x,y) \to (x,-y)

<h3>Nonrigid transformation</h3>

When a shape is transformed by a nonrigid transformation, then the image of the shape will not be congruent to the original shape, however the original shape and the transformed shape would be similar

An example of a nonrigid transformation is a dilation by a scale factor od 0.5; and the rule is:

(x,y) \to (0.5x,0.5y)

So, a rule that will take the triangle to a figure that is similar is (x,y) \to (0.5x,0.5y)

However, if the x and y coordinates of the shape are dilated by different scale factors, then the resulting shape would neither be similar nor be congruent to the original shape.

A rule that will take the triangle to a figure that is not similar or congruent is (x,y) \to (0.5x,2y).

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