All categories

2 years ago

Using the paths shown, the distance from Brookfield to Seaside is 20.4 kilometers.

Mathematics

1 answer:

stepan [7]2 years ago

7 0

Answer:

7.2 km

Step-by-step explanation:

Distance between Brookfield to Seaside = 20.4 km

Distance between Yardley and Seaside = 13.2 km

Let distance between Brookfield to Yardley be x.

Thus:

x + 13.2 km = 20.4 km

Subtract 13.2 from each side

x = 20.4 - 13.2

x = 7.2

Distance from Brookfield to Yardley is 7.2 km

You might be interested in

Describe all situation where vertical angles are also supplementary

Nataly_w [17]

Vertical angles are always the same size. if they are supplementary the measures must add to 180. 180/2=90. vertical angles are supplementary only when they are right angles, our 90°

3 0

3 years ago

Read 2 more answers

The greater of two numbers is 5 more than the smaller. If the

xenn [34]

Answer:

First number = 4

Second number = 9

Step-by-step explanation:

If the first number = x, the second number = x + 5.

The calculation can be expressed as follows:

x + 2(x + 5) = 22

First, expand the bracket 2(x + 5):

x + 2x + 10 = 22

Combine like terms:

3x + 10 = 22

Subtract 10 from both sides:

3x = 12

Divide both sides by 3:

x = 4

First number = 4

Second number = 4 + 5 = 9

5 0

1 year ago

Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.

mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = $^{6}C_{1}\times^{4}C_{3}=6\times4$ =24

2 Boy and 2 girls= $^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90$

3 Boys and 1 girl = $^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80$

4 Boys = $^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15$

Now total number of ways = 24 + 90 + 80 + 15 = 209

7 0

3 years ago

Factor completely -5x 2 y + 10xy - 15xy 2

victus00 [196]

-5x^2 y + 10xy - 15xy^2

= -5xy(x - 2 + 3y)

8 0

2 years ago

Read 2 more answers

A store marks up sweaters by 23%. Find the retail price of a sweater originally priced at<br>$48.

34kurt

Answer:

The mark up price of the sweater would be $59.04

8 0

2 years ago