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Ann [662]
3 years ago
15

I need help please and thank you so much

Mathematics
1 answer:
nikitadnepr [17]3 years ago
6 0

Answer: first choice

Step-by-step explanation

F= v+at

-v=-v

F-v=at

Divide by t

F-V/t= a

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Can someone explain this to me please will give brainliest
KATRIN_1 [288]
The answer is A. for this, you have to set up a system of equations. the first one will be the area equation. since you know area=length x width, your equation will be LxW=50. the next equation is L=2W, since the length is two times the width. then, plug in 2W for the L in the other equation and you get 2W^2=50. divide by 2 and get W^2=25. square root both sides and you get W=5. plug back into the other equation to find L=10. Then, add the sides of the rectangle for the perimeter. 10+5+10+5=30.
3 0
3 years ago
In creating a new scale for the mercury thermometer, anders celsius initially set the boiling point of water at _____. a. 0° b.
anastassius [24]

Answer: 100 °

Step-by-step explanation:

6 0
2 years ago
Find the slope of the line that passes through (8, 3) and (1, 9).
leonid [27]

Answer:

-\frac{6}{7}

Step-by-step explanation:

⇒ m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

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⇒ m = \frac{6}{-7}

3 0
2 years ago
What is the surface area of a cylinder that has the following measurements? area of each base: 50.24 ft2 area of lateral surface
irinina [24]

Answer:

TSA = 175.84 ft²

Step-by-step explanation:

We are given;

Lateral surface area; A_L = 75.36 ft²

Area of base; A_b = 50.24 ft²

Height of cylinder; h = 3ft

Formula for total surface area of Cylinder is;

TSA = 2πr² + 2πrh

Now, lateral surface area is given by the formula; A_L = 2πrh

Area of base is given by the formula;

A_b = πr²

Thus, let's apply these 2 formulas to the formula for total surface area;

TSA = 2(Area of base) + Lateral surface area

TSA = (2 * 50.24) + 75.36

TSA = 175.84 ft²

3 0
3 years ago
Given: M(-4,-1), B(-5,-3) find the midpoint
Dmitry [639]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
M&({{ -4}}\quad ,&{{ -1}})\quad 
%  (c,d)
B&({{ -5}}\quad ,&{{ -3}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -5}}-4}{2}\quad ,\quad \cfrac{-3-1}{2} \right)
4 0
4 years ago
Read 2 more answers
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