Answer:
Molarity of acid soln = 0.176M
Explanation:
Molarity of NaOH soln x Volume of NaOH soln = Molarity of acid soln x Volume of acid soln
=> 26.23ml x 1.008M = 150.2ml x Molarity of acid solution
=> Molarity of acid soln = (26.23ml)(1.008M)/(150.2ml) = 0.176M
I know the last section is chemical and light but im not sure about the first if i had to guess it would be kinetic
The number of moles of b2o3 that will be formed is determined as 4 moles.
<h3>
Limiting reagent</h3>
The limiting reagent is the reactant that will be completely used up.
4 b + 3O₂ → 2b₂O₃
from the equation above;
4 b ------------> 2 b₂O₃
2b ------------> b₂O₃
2 : 1
3O₂ -------------> 2b₂O₃
3 : 2
b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;
4 b ------------> 2 moles of b2o3
8 moles -------> ?
= (8 x 2)/4
= 4 moles
Thus, the number of moles of b2o3 that will be formed is determined as 4 moles.
Learn more about limiting reactants here: brainly.com/question/14222359
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Answer:
0.0002949 moles
Explanation:
Concentration = 2.02×10−2 M
Volume = 14.6 mL = 0.0146 L (Upon converting to litres)
Number of moles = ?
These variables are related by the fllowing equation;
Concentration = Number of moles / Volume
Number of moles = Concentration * Volume
Number of moles = 2.02×10−2 * 0.0146 = 0.0002949 moles
