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Mama L [17]
3 years ago
11

First time doing mensuration, can someone enlighten me on how to find the height of the hemisphere and cone?

Mathematics
2 answers:
muminat3 years ago
8 0

Answer:

3 cm and 4 cm.

Step-by-step explanation:

The height of the hemisphere is the same as its radius, 3 cm.

The height of the cone = 7 - 3 = 4 cm.

Alina [70]3 years ago
4 0

Answer:

Step-by-step explanation:

volume=1/3\pi  r^2h +2/3\pi r^3[

tex]=1/3\pi *9*4+2/3\pi  *3^3[/tex]

=12\pi +18\pi= 30 \pi volume

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ad-work [718]

Answer:

4a^2 (8a+3)

Step-by-step explanation: it’s right

5 0
3 years ago
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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

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P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

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if friend is 55 feet tall and casts a shadow that is 3.53.5 feet long. What is the height of the bird house?
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First subtract -19 - 1 = -20

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